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Sati [7]
3 years ago
10

If x= -6 and y = 2, evaluate the following expression: x²y + x . .

Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
66 is the answer
....
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Expand (x+2y)^2<br>hgghhhhjjjjjjj​
Sonbull [250]

Step-by-step explanation:

(x+2y)²=x²+4xy+4y²

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7 0
3 years ago
Brainlest!!!
son4ous [18]

Answer:

1st graph: x ≤ -5

2nd graph: x > -5

3rd graph: x ≥ -5

4th graph: x > 5

Step-by-step explanation:

5 0
3 years ago
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Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win
Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Similarly,

P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

7 0
3 years ago
What is 37.025 written in word format
egoroff_w [7]
Thirty seven and twenty five thousandths

6 0
3 years ago
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Help!!! ASAP how to graph this!!!! Exaplain or graph it n send the pic
ankoles [38]

Answer:

https://www.symbolab.com/graphing-calculator

Step-by-step explanation:

this is a great thing to use

5 0
3 years ago
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