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3 years ago

How to calculate the slope of position time graph ?

Physics

1 answer:

meriva3 years ago

8 0

Answer:

Slope= $\frac{x2-x1}{t2-t1}$

Explanation:

We are supposed to find the slope in a position time graph,

For that we need atleast two points $(t1,x1),(t2,x2)$ .( $(x,y )$ represents there coordinates in respective axis directions.)

In the given case the y axis would be the position and the x axis as time .

Slope is defined as the ratio of change in y coordinate to change in x coordinate :- $\frac{y2-y1}{x2-x1}$

So subsituting the coordinates of position and time we get slope as:-

$\frac{x2-x1}{t2-t1}$

[When we have more than two points which are not collinear then to calculate the slope we take the average.]

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A tire is filled with air at 10 ∘C to a gauge pressure of 250 kPa. Part A If the tire reaches a temperature of 45 ∘C, what fract

Alex_Xolod [135]

Answer:

The air fraction to be removed is 0.11

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Initial temperature, T = $10^{\circ}$ = 283 K

Pressure, P = 250 kPa

Finally its temperature increases, T' = $45^{\circ}$ = 318 K

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Using the ideal gas equation:

PV = mRT

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P = Pressure

V = Volume

m = no. of moles of gas

R = Rydberg's Constant

T = Temperature

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Considering the eqn at constant volume and pressure, we get:

mT = m'T'

Thus

$\frac{m}{m'} = \frac{T'}{T}$ (1)

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$y = \frac{m - m'}{m} = 1 - \frac{m'}{m}$

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$y = 1 - \frac{T}{T'}$

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