Which of the following is the correct definition of conduction?

For single bonds between similar types of atoms, how does the strength of the bond relate to the sizes of the atoms? Explain.

uysha [10]

When comparing single bonds between atoms of comparable types, the stronger the bond is, the bigger the atom, the weaker it is.

The length of the X-H bond lengthens while the strength of the bond shortens with increasing halogen size (F-H strongest, I-H weakest). When comparing single bonds between atoms of similar sorts, the larger the atom, the weaker the bond. It can be explained by the fact that less energy is required to break the bond the bigger the atom's atomic size. The force of attraction from the nucleus to the outermost orbit will be less for iodine since it has a larger atom than the other elements in the group.

Learn more about single bonds here-

brainly.com/question/16626126

#SPJ4

7 0

1 year ago

The ka of phosphoric acid, h3po4, is 7.6  10–3 at 25 °c. for the reaction h3po4(aq) h2po4 – (aq) + h+ (aq) ∆h° = –14.2 kj/mol.

blsea [12.9K]

Use the van't Hoff equation: ln ( K2 K1 ) = Î” HÂş R ( 1 T1 â’ 1 T2 ) ln ( K2 7.6*10^-3 ) = -14,200 J 8.314 ( 1 298 â’ 1 333 ) ln ( K2 7.6*10^-3 ) = â’ 1708 ( 0.00035 ) ln ( K2 0.0076 ) = â’ 0.598 Apply log rule a = log b b a -0.598 = ln ( e â’ 0.598 ) = ln ( 1 e 0.598 ) Multiply both sides with e^0.598 K 2 e 0.598 = 0.0076 K e 0.598 e 0.598 = 0.0076 e 0.598 K 2 = 0.0076 e 0.598 = 4.2 â‹… 10 â’ 3 K2 = 4.2 â‹… 10 â’ 3

7 0

3 years ago

You need 455 ml of a 75% alcohol solution. on hand, you have a 25% alcohol mixture. you also have a 90% alcohol mixture. how muc

marishachu [46]

X ml - 25% alcohol mixture
y ml - 90% alcohol mixture

x+y = 455

0.25x ml alcohol in x ml of 25% alcohol mixture
0.9y ml alcohol in y ml of 90% alcohol mixture
0.75*455= 341.25 ml alcohol in 455 ml of 75% alcohol mixture

0.25x+0.9y=341.25

System of equations:

x+y = 455 /*(-0.25) ------> -0.25x-0.25y = -0.25*455
0.25x+0.9y=341.25

-0.25x-0.25y=-113.75
0.25x+0.9y=341.25 Add both equations

0.25x+0.9y-0.25x-0.25y=341.25-113.75
0.65y =227.5
y=227.5/0.65 = 350 ml of 90% alcohol mixture

x+y=455
x+355=455
x=100 ml of 25% alcohol mixture

8 0

3 years ago

Answer? giving brainlyest

salantis [7]

Answer:

r=3

Explanation:

6 0

3 years ago

What bond vibrations and stretching frequencies should you observe in the IR spectrum of caffeine?

Margarita [4]

The bond vibrations that can be observed in the IR spectrum of caffeine :

i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking

while the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.

Caffeine is a polyatomic molecule ( contains more than two atoms bonded via covalent bonds ) therefore its atoms can vibrate in three dimensions ( x, y, z ).therefore the bond vibrations that can be observed in the IR spectrum of caffeine are : asymmetric, symmetric, wagging, twisting, scissoring, and rocking.

The observable stretching frequencies that are in the IR spectrum of caffeine ; C = O is 1700 , C - H is 1300, C -H is 2900, C -N is 1500, and N -H = 3000.

Hence we can conclude The bond vibrations that can be observed in the IR spectrum of caffeine : i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking and the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.

Learn more : brainly.com/question/13184210

3 0

2 years ago