As aluminium loses 12 moles of electrons oxygen gain 12 moles of electrons.
Explanation
4Al + 3 O2→ Al2O3
first write the ions of Aluminium and oxygen
that is, Aluminium ion is = Al^3+
oxygen ion is = O^2-
therefore one atom of Al loses 3 electrons moles while
one atom of O gain 2 electrons moles
from equation above there a total of number of Al atom are 4 =( 1 x4=4) atoms while
Oxygen atoms are 6= ( 3 x2=6) atoms
therefore the total number of Moles of Al lost is = 3 x 4 = 12 moles of electrons
total number of moles of O gained = 2 x6 = 12 moles of electrons
Answer:
The correct answer is 27.764 grams.
Explanation:
A standard scientific unit for determining the large quantities of very small entities like molecules, atoms, or other specific particles is termed as a mole. The molecular weight of lithium is 6.941 grams per mole. Thus, one mole of lithium has 6.941 grams.
If, 1 mole of Li has 6.941 grams, then 4 moles of Lithium will have,
= Molecular mass of lithium/1 mole * 4 mole
= 6.941 gram per mole/1 mole * 4 moles.
= 27.764 grams
Answer:
The student's conclusion is not correct
Explanation:
Activation energy is the minimum amount of energy required for a reaction to occur. All reactions require there activation energy to be met before the reaction can proceed. When the temperature of a reaction is increased, the kinetic energy of the reactant molecules increases; colliding more with each other, which makes them "surmount" the activation energy of the reaction faster as compared to a lower temperature.
In combustion, there is burning of an hydrocarbon (in this case propane) in excess oxygen. The burning assists in increasing the kinetic energy of the reactant particles which in turn easily surmounts the activation energy of the reaction by colliding (effective collision) more with oxygen. So, the reaction has an activation energy but the activation energy has been met and passed and hence the reaction is proceeding faster.
Increasing the temperature of a reaction is one of the ways of increasing the rate of a chemical reaction.