Explanation:
At the maximum height, the ball's velocity is 0.
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (12.3 m/s)² + 2(-9.80 m/s²)(x - 0 m)
x = 7.72 m
The ball reaches a maximum height of 7.72 m.
The times where the ball passes through half that height is:
x = x₀ + v₀ t + ½ at²
(7.72 m / 2) = (0 m) + (12.3 m/s) t + ½ (-9.8 m/s²) t²
3.86 = 12.3 t - 4.9 t²
4.9 t² - 12.3 t + 3.86 = 0
Using quadratic formula:
t = [ -b ± √(b² - 4ac) ] / 2a
t = [ 12.3 ± √(12.3² - 4(4.9)(3.86)) ] / 9.8
t = 0.368, 2.14
The ball reaches half the maximum height after 0.368 seconds and after 2.14 seconds.
Answer:
The ground pushes back on your feet with equal force
Explanation:
When you walk across the ground and push on it with your feet, the ground pushes back on your feet with an equal and opposite force.
This interpretation and knowledge is gotten from Newton's third law of motion.
It states that "action and reaction force are equal and opposite in nature".
- The force applied to a body responds with an opposite force in the other direction.
- Therefore, the reaction force is of equal magnitude but directed in another direction.
Answer:
This is a paradox — an inconsistency that often leads people to think that time travel cannot occur in our universe." A variation is known as the "grandfather paradox" — in which a time traveler kills their own grandfather, in the process preventing the time traveler's birth
Explanation:
hope this Wil help ....
Answer:
170 N
Explanation:
Since Force F = ma were m = mass = 85 kg and a = acceleration = 2.0 m/s².
So the net force on the bicycle is
F = ma = 85 kg × 2.0 m/s² = 170 N
Answer:
The grating spacing of the beetle is 
Explanation:
The concept to solve this problem is relate to interference effect given in the Young's Slits. Here was demonstrated that the length of the side labelled \lambda is known as the path difference. The equation is given by,

Where,
= wavelenght of light
N = a positive integer: 1,2,3...
= Angle from the center of the wall to the dark spot
d= width of the slit
Replacing our values we have that for n=1,



Therefore the grating spacing of the beetle is 