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3 years ago

When converted to a household measurement, 9 kilograms is approximately equal to a

Physics

1 answer:

mariarad [96]3 years ago

3 0

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

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How many Fahrenheit degrees are needed to equal one Celsius (or Kelvin) degree?

Nat2105 [25]

One Celsius degree is the same size as one Kelvin. Each of them is the size of 1.8 Fahrenheit degrees.

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3 years ago

A +1.0 nC charge is at x = 0 cm, a -1.0 nC charge is at x = 1.0 cm and a 4.0 nC at x= 2 cm. What is the electric potential energ

lesantik [10]

Answer:

- 2.7 x 10^-6 J

Explanation:

q1 = 1 nC at x = 0 cm

q2 = - 1 nC at x = 1 cm

q3 = 4 nC at x = 2 cm

The formula for the potential energy between the two charges is given by

$U=\frac{Kq_{1}q_{2}}{r}$

where r be the distance between the two charges

By use of superposition principle, the total energy of the system is given by

$U = U_{1,2}+U_{2,3}+U_{3,1}$

$U=\frac{Kq_{1}q_{2}}{0.01}+\frac{Kq_{2}q_{3}}{0.01}+\frac{Kq_{3}q_{1}}{0.02}$

$U=-\frac{9\times10^{9}\times 1\times10^{-9}\times 1\times10^{-9}}}{0.01}-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.01}+-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.02}$

U = - 2.7 x 10^-6 J

3 0

3 years ago

What will be the change in velocity of a 850kg car if a force of 50,000 N

yKpoI14uk [10]

Answer:

29.412m/s

Explanation:

$F=ma$ where F= force, m= mass, and a=acceleration

we also know that,

a = Δv / t where Δv = change in velocity and t = time

thus F = m ( Δv / t)

$50000=850(\frac{v}{0.5})$

$\frac{50000}{1700}=$ Δv

29.412m/s=Δv

8 0

3 years ago

bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s what is the veloci

spin [16.1K]

Answer: V1 = 3.559 - 0.744V2

Explanation: Given that the

bumper car A has

Mass M1 = (281 kg) moving with

Velocity U1 = 2.82 m/s

bumper car B has

Mass M2 = (209 kg) moving with

Velocity U2 = 1.72 m/s

Where U1, U2 are the initial velocity of the two cars

Since the collision is elastic, we will use the formula below,

M1U1 + M2U2 = M1V1 + M2V2

Substitute the values into the formula

281×2.28 + 209×1.72 = 281V1 + 209V2

640.68 + 359.48 = 281V1 + 209V2

1000.16 = 281V1 + 209V2

Make V1 the subject of formula

281V1 = 1000.16 - 209V2

V1 = 1000.16/281 - 209V2/281

V1 = 3.559 - 0.744V2

Therefore, the velocity of car A which

is V1 after the collision will be expressed as V1 = 3.559 - 0.744V2

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3 years ago

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Musya8 [376]

Monsoon is a blah blah hahahahah adding for someone

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3 years ago