All categories

3 years ago

Carbon containing compounds are referred to as:

Chemistry

1 answer:

Flura [38]3 years ago

3 0

Organic compounds
If you need an explanation I can give one!

You might be interested in

100 POINTS ANSWER FAST

alex41 [277]

I believe the answer is a because 2 times 12 is 24. Hope this helped

8 0

3 years ago

Read 2 more answers

Ethanol, 1-octanol, methanol and 3-methyl-1-butanol contain what functional group characteristics of all alchohols

Amiraneli [1.4K]

Answer:

The hydroxyl group

Explanation:

The molecular formulas of the above alcohols are

CH₃CH₂-OH

CH₃CH₂CH₂CH₂CH₂CH₂CH₂CH₂-OH

CH₃-OH

CH₃CH(CH₃)CH₂CH₂-OH

The functional group that is characteristic of all alcohols is the hydroxyl group (-OH).

6 0

3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{E}{E'}=\sqrt{\frac{M'}{M}}$

$\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}$

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0

3 years ago

An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda

DENIUS [597]

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = $\frac{5}{100}=0.05$

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = $\frac{95}{100}=0.95$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(113\times 0.05)+(115\times 0.95)]$

$A=114.9amu$

Thus its average atomic mass is 114.9 amu

5 0

3 years ago

Which atom’s ionization energy is greater than that of phosphorus (P)? A. Ba B. K C. As D. Cl

WINSTONCH [101]

Answer is: D. Cl (chlorine).

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

Barium, potassium and arsenic are metals (easily lost valence electrons), chlorine is nonmetal (easily gain electrons).

Alkaline metals (in this example, potassium) have lowest ionizations energy and easy remove valence electrons (one electron), earth alkaline metals (in this example, barium) have higher ionization energy than alkaline metals, because they have two valence electrons.

Nonmetals (in this example chlorine) are far right in the main group and they have highest ionization energy, because they have many valence electrons.

5 0

3 years ago