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3 years ago

How are the properties of sodium chloride different than sodium and chlorine

1 answer:

7 0

<span>Sodium chloride is formed when sodium atoms interact with chlorine atoms. When this occurs, sodium will donate an electron (which is a negatively-charged particle) to chlorine. This makes sodium slightly positive and chlorine slightly negative. ... So then, sodium ions will attract chloride ions and form an ionic bond.</span>

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Predict what might happen if the human body did not have specialized cells, tissues, organs, and organ systems to maintain homeo

bekas [8.4K]

We would be dead. No heart, brain or blood flow <span />

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3 years ago

Read 2 more answers

There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride, molecular formula ) at thre

RideAnS [48]

Answer:

The correct answer is - option C.

Explanation:

Given: the melting point of HCl is

-114.8 °C, which suggests that below this temperature HCl will be solid.

and, since the boiling point of HCl is - 85.1 °C. It is also suggested that above this temperature HCl will be gas, Therefore.

Solid -114.8 - Ordered arrangement

Liquid -85.1c - Less orderly arranged

Gaseous - Least orderly arranged

Thus, at —90 °C, HCl will be present 'in the liquid state, At — 1 °C, HCl will be present in the gaseous state and at -129 °C, HCl will be present in the solid-state. So, the molecules will be organized in a more orderly manner .

Thus, the correct answer is - option C

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3 years ago

4. Which atomic particles are found inside the nucleus of an atom?

grin007 [14]

Answer:

the atomic particles in the necluse are called ions which are positive and negive charged atoms

Explanation:

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3 years ago

If you wanted to protect water from freezing, which of the compounds below would accomplish this best. NaNO3, Mg(NO3)2, or Al(NO

Korvikt [17]

All of them are soluble salt.

First one dissociates into two ions.

The second one dissociates into 3 ions.

The third dissociate into 4 ions. therefore, Al(NO3)3

4 0

3 years ago

If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution?

Alborosie

Concentration is the number of moles of solute in a fixed volume of solution

Concentration(c) = number of moles of solute(n) / volume of solution (v)

25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.

original solution molarity - 0.150 M

number of moles of LiOH in 1 L - 0.150 mol

number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol

when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases

new volume - 125 mL + 25 mL = 150 mL

therefore new molarity is

c = 0.01875 mol / 0.150 L = 0.125 M

answer is 0.125 M

7 0

3 years ago