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rewona [7]
3 years ago
5

Why was it important to have endothermic and exothermic processes in the building materials of your train?

Chemistry
1 answer:
atroni [7]3 years ago
5 0
Before, trains worked using the steam engine. Thus, it uses heat so it is crucial to apply heat balance. The steam engine absorbs energy during the stage of boiling water. So, this is the endothermic reaction. When the steam is used to work the piston, it has to release this energy through running the train. The excess energy is released as an exhaust to the chimney. This is the exothermic process because it releases energy to the surroundings.
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A liquid has a density of 4.26g/ml. It has a mass of 2.2g. What is the volume of the liquid?
serg [7]

Answer:

Volume = .5164 ml

Explanation:

These are the equations you need to learn.

Density = \frac{mass}{volume}

Volume = \frac{Mass}{Density}

Mass = Density * Volume

Apply these concepts to your problem

4.26 g/ml = \frac{2.2g}{x}

V = \frac{2.2g}{4.26g/ml}

Divide 2.2/4.26

V = 0.5164319248826291

Volume = .5164ml

5 0
3 years ago
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The text of oxygen gas in the laboratory ​
IgorC [24]

Explanation:in testing for oxygen a glowing splint is used.

the glowing splint is brought in the presence of the test tube containing the gas

the glowing splint rekindles or lights up showing that oxygen is present.

this is a positive test because oxygen supports burning or combustion

8 0
3 years ago
Ethanol has a density of 0.79g/mL what is the volume, in quarts, of 1.50 kg of ethanol?​
lara31 [8.8K]

Answer:

2.01 qt

Explanation:

4 0
3 years ago
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A 20.0-milliliter sample of 0.200 M K2CO3 solution is added to 30.0 milliliters of 0.400 M Ba(NO3)2 solution.
jenyasd209 [6]

Answer:

(B) 0.160 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For K_2CO_3 :

Molarity = 0.200 M

Volume = 20.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 20.0×10⁻³ L

Thus, moles of K_2CO_3 :

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles of K_2CO_3 = 0.004 moles

For Ba(NO_3)_2 :

Molarity = 0.400 M

Volume = 30.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume =30.0×10⁻³ L

Thus, moles of Ba(NO_3)_2 :

Moles=0.400\times {30.0\times 10^{-3}}\ moles

Moles of Ba(NO_3)_2  = 0.012 moles

According to the given reaction:

K_2CO_3_{(aq)}+Ba(NO_3)_2_{(aq)}\rightarrow BaCO_3_{(s)}+2KNO_3_{(aq)}

1 mole of potassium carbonate react with 1 mole of barium nitrate

0.004 moles potassium carbonate react with 0.004 mole of barium nitrate

Moles of barium nitrate  = 0.004 moles

Available moles of barium nitrate  =  0.012 moles

Limiting reagent is the one which is present in small amount. Thus, potassium carbonate is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of potassium carbonate gives 1 mole of barium carbonate

Also,

0.004 mole of potassium carbonate gives 0.004 mole of barium carbonate

Mole of barium carbonate = 0.004 moles

Also, consumed barium nitrate = 0.004 moles  (barium ions precipitate with carbonate ions)

Left over moles = 0.012 - 0.004 moles = 0.008 moles

Total volume = 20.0 + 30.0 mL = 50.0 mL = 0.05 L

So, Concentration = 0.008/0.05 M = 0.160 M

<u>(B) is correct.</u>

4 0
3 years ago
Write the balanced equation for the spontaneous cell reaction that occurs in a cell with these reduction half-reactions.
lbvjy [14]

Answer:

     HelloHelloHelloHelloanswer answeranswer answer

4 0
2 years ago
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