Answer:
<h2>13.64 L</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
From the question we have
From the question we have
We have the final answer as
<h3>13.64 L</h3>
Hope this helps you
Answer:
It damaged the environment growth of humans and the population had a negative affect on the environment
Explanation:
Answer:
The molarity of the sulfuric acid is 0.018 M
Explanation:
The molarity of a solution is the number of moles of the solute (sulfuric acid in this case) in a 1-liter solution.
Every 100 g of the solution, we have 95 g sulfuric acid because its concentration is 95% w/w.
With the density, we can calculate how many liters are 100 g of solution:
density = mass / volume
1.85 g / ml = 100 g / volume
volume = 100 g / 1.85 g/ml
volume = 54.1 ml or 0.0541 l
Now, we know that we have 95 g sulfuric acid in 0.0541 l solution. In 1 l, we have then:
1 l * 95g / 0.0541 l = 1.756 g sulfuric acid.
But we want to know how many moles sulfuric acid we have per liter. Then, using the molar mass, we can calculate how many moles there are in 1.756 g sulfuric acid:
1.756 g * 1 mol / 98.08 g = 0.018 mol
The molarity is 0.018 M
This isn't a full question!
Answer:
Option E is correct. none of the above is correct
Explanation:
Step 1: Data given
Solid Iron (III) = Fe^3+
iron (III) oxide = Fe2O3
Molar mass Fe = 55.845 g/mol
Molar mass Fe2O3 = 159.69 g/mol
Step 2: The balanced equation:
4Fe + 3O2 → 2Fe2O3
4 moles of iron will need 2 moles of oxygen gas to fully react
⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react
B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.
⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3
C.9 moles of oxygen can produce 9 moles of Iron (III) oxide
⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3
D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.
⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3
E.none of the above
