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Oliga [24]
2 years ago
14

Please answer these 2 questions. I promise to mark as brainliest if you can solve with steps. Thank you.

Mathematics
1 answer:
neonofarm [45]2 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

4

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{BC}{EF} = \frac{AB}{DE} ( substitute in values )

\frac{x-1}{18} = \frac{4}{12} ( cross- multiply )

12(x - 1) = 72 ( divide both sides by 12 )

x - 1 = 6 ( add 1 to both sides )

x = 7

------------------------------------------------------------------------------

5

The parallel line segment SV is half of RW

that is x = 7.5

SV also divides the sides RT and WT in proportion, that is

\frac{10}{3} = \frac{8}{y} ( cross- multiply )

10y = 24 ( divide both sides by 10 )

y = 2.4

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Step-by-step explanation:

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What is the answer to this math question
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Answer:

11

Step-by-step explanation:

1.80m + 0.6s = 12.00

[substitute the value of m into the equation]

1.80×(3) + 0.6s = 12

5.4 + 0.6s = 12

[make s the subject of the formula]

0.6s = 12 - 5.4

0.6s = 6.6

[divide both sides of the equation by 0.6]

0.6s / 0.6 = 6.6 / 0.6

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To prove that 11 is correct

[substitute the value of m and s into the equation]

1.80m + 0.6m = 12.00

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I need help on number 6 plz!
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8 0
2 years ago
Which of the following equations might have the graph shown?
jonny [76]

we will select each options and then we verify it

(a)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=2 but k=-3

so, this is FALSE

(B)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=3 and k=4

so, this is TRUE

(C)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=-3 and k=-4

so, this is FALSE

(D)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=5 and k=5

so, this is TRUE

(E)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , we have all terms positive

so, h and k must be negative here

so, this is FALSE

(E)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , we have -4x and -6y

which will have h and k positive

so, this is TRUE

8 0
3 years ago
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