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muminat
3 years ago
7

Describe how you can determine:a) Volume of an irregular bodyb) Density of a liquid​

Physics
2 answers:
vlada-n [284]3 years ago
7 0

Density of liquid try thank you so much

nirvana33 [79]3 years ago
5 0

Answer:

  a) measure the change in volume when the object is immersed; compute from range data

  b) find the ratio of mass to volume for a measured mass and volume

Explanation:

a) The volume of a small enough irregular body can be found by measuring the difference in volume of the (semi-)fluid in which it is immersed, before and after immersion.

For irregular bodies for which that approach does not work, various 3D scanners are available for measuring volume and surface area. They may rely on optical (laser or camera), sonic, or radar measurements, and generally involve computation from distances to various points.

__

b) Density is the ratio of mass to volume. So, measurements of mass and volume of a liquid sample are sufficient to provide the basis for determining density.

Other methods include measuring buoyancy forces, and/or the depth of submersion of something that floats in the liquid. For specific liquids, hydrometers are available for measuring their density relative to that of water.

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light traveling through air encounters a second medium which slows the light to 100,000 miles/second. What is the index of the s
IceJOKER [234]

Answer:

300000 hope it is help full

Explanation:

300000

6 0
2 years ago
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A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows
Alona [7]

Answer:

1) The girl's acceleration at time 't' is, a=0.47 m/s²

2) The girl's acceleration at time 't₁' is, a_{1}=0 m/s²

3) The girl's acceleration at time 't₂' is,  a_{2}=-0.14 m/s²

Explanation:

Given data,

The initial walking speed of the girl, u = 0

The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s

The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s

The girl slows down and comes to a stop during a period, t₂ = 10 s

1) The girl's acceleration at time 't'

                                a=\frac{v-u}{t}

                                a=\frac{1.4-0}{3}

                               a=0.47 m/s²

2) The girl's acceleration at time 't₁'

                                a_{1} =\frac{v_{1} -v}{t_{1}}

                                a_{1}=\frac{1.4-1.4}{6}

                               a_{1}=0 m/s²

3) The girl's acceleration at time 't₂'

                                a_{2} =\frac{v_{2} -v_{1}}{t_{2}}

                                a_{2}=\frac{0-1.4}{10}

                               a_{2}=-0.14 m/s²

4 0
3 years ago
1. Order the materials from smallest refractive index to largest refractive index.
slavikrds [6]

Air = 1

Water = 1.33

Glass = 1.52

Quartz = 1.46

Diamond = 2.42

3 0
3 years ago
Moving company uses a machine to raise a 900 Newton refrigerator to the second floor of a building machine consists of a single
Juliette [100K]
Mechanical advantage of a machine is the ratio of the output force over the input force or M=Fo/Fi. Since M=1, Fi=Fo, or the input force is equal to the output force. This means that to raise the refrigerator that weighs 900 N, we need the same input force of 900 N, or Fo=Fi=900 N. 
6 0
3 years ago
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A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

2.7 s = \frac{18}{v}

v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

6.67 = \sqrt{\frac{T}{0.67}}

so we will have

T = 29.6 N

5 0
4 years ago
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