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Pani-rosa [81]
3 years ago
5

Based on the information presented in the graphs above, how does temperature affect solubility

Chemistry
1 answer:
Stells [14]3 years ago
6 0

Answer:Temperature is directly proportional with gas , liquid and solid in its decreasing form

Explanation:So when temperature rises the the solubility of a substance also increases with it where as when it decreases it also decreases with temperature

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What region of the atom contains most of the atoms mass?
dimulka [17.4K]

Answer:

Nucleus

Explanation: it is the center of the atom, and contains protons and nuetrons

7 0
3 years ago
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For 2,663 kg of a compound with the formula Al(SO), determine the following quantities (4 pts each); a) The number of moles of t
Nastasia [14]

Answer:

a) 35.485 moles of Al(SO)

b) 35.485 moles of S atoms

c) 2.136197(10^{25}) Al atoms

d) 567.723 g of O

Explanation:

Let's define the following terms :

1 mol = 6.02.(10^{23}) elemental units

For example :

1 mol of oxygen atoms = 6.02.(10^{23}) oxygen atoms

Now, our compound has the following formula

Al(SO)

Where Al is aluminium

S is sulfur

And O is oxygen

All the subscripts are 1 so we can say the following :

1 molecule of Al(SO) has 1 atom of Al , 1 atom of S and 1 atom of O

In terms of moles :

1 mol of Al(SO) has 1 mol of Al , 1 mol of S and 1 mol of O

The molar masses of Al, S and O are

molarmass_{(Al)}=26.982\frac{g}{mol}

molarmass_{(S)}=32.065 \frac{g}{mol}

molarmass_{(O)}=15.999\frac{g}{mol}

If we sum all the molar masses =(26.982+32.065+15.999)\frac{g}{mol}=75.046\frac{g}{mol}

Finally, 75.046 g of Al(S0) is 1 mol of Al(SO) which contains 26.982 g of Al, 32.065 g of S and 15.999 g of O.

1 mol of Al(SO) contains 1 mol of Al, 1 mol of S and 1 mol of O.

Now we can calculate a),b),c) and d)

For a)

2.663 kg=2663g

75.046 g of Al(SO) = 1 mol of Al(SO)

2663 g of Al(SO) = x

x=\frac{2663}{75.046}mol=35.485 mol

2.663 kg of Al(SO) contains 35.485 moles of Al(SO)

b) and c) 1 mol of Al(SO) molecules contains 1 mol of S atoms and 1 mol of Al atoms

We have 35.485 moles of Al(SO) molecules so

We have 35.485 moles of S atoms

And 35.485 moles of Al atoms

If 1 mol = 6.02(10^{23})

35.485 moles of Al have (35.485)(6.02)(10^{23})=2.136197(10^{25}) Al atoms

d) 75.046 g of Al(SO) contains 15.999 g of O

2663 g of Al(SO) contains x g of O

x=\frac{(2663).(15.999)}{75.046} g

x = 567.723 g of O

6 0
3 years ago
A 25.0 mL sample of 0.123 M HCl was titrated with 18.04 mL of NaOH . What is the concentration of the NaOH ?
Blababa [14]

Answer:

0.170 M

Explanation:

M1V1=M2V2

(25.0mL)(0.123M)=(18.04mL)(x)

x= 0.170 M

* Please text me at 561-400-5105 for tutoring: I can do assignments, labs, exams, etc. :)

5 0
3 years ago
37.5ml of menthol is dissolved in water to make 456 ml of solution, what is the concentration expressed in volume/volume % of th
Ahat [919]

Answer:

V/V% = 8.2%

Explanation:

Given data:

Volume of methanol = 37.5 mL

Volume of solution = 456 mL

V/V% = ?

Solution:

V/V% = [volume of solute / volume of solution ]×100

V/V% = 37.5 mL / 456 mL × 100

V/V% = 0.08× 100

V/V% = 8.2%

3 0
3 years ago
Someone pls tell me the answer
notka56 [123]

Answer:

6 inches and that should be the answer

6 0
3 years ago
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