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kolbaska11 [484]
3 years ago
15

What is the solution to the problem expressed to he correct number of significant figures? 12.0/7.11

Chemistry
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer: The solution to the problem expressed to he correct number of significant figures is 1.69

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule applied for multiplication and division is :

The least precise number determines the number of significant figures in the answer.

As 12.0 has 3 significant digits and 7.11 also has 3 significant digits, the answer would also contain 3 significant digits.

For \frac{12.0}{7.11}=1.69

Thus the solution to the problem expressed to he correct number of significant figures is 1.69

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Which pH indicates a substance that is more acidic than a substance with a pH of 4
dexar [7]
Anything with a pH level of 3, 2, or 1.
8 0
3 years ago
The volume of carbon gas at 5.0 ATM was measured to be 363 ml. What will the pressure be if the volume is change to .00020 ml?
aleksley [76]

Answer:

The answer to your question is P2 = 9075000 atm

Explanation:

Data

Pressure 1 = P1 = 5 atm

Volume 1 = V1 = 363 ml

Pressure 2 = P2 = ?

Volume 2 = 0.0002 ml

Process

To solve this problem use Boyle's law

                 P1V1 = P2V2

-Solve for P2

                 P2 = P1V1/V2

-Substitution

                  P2 = (5 x 363) / 0.0002

-Simplification

                  P2 = 1815 / 0.0002

-Result

                 P2 = 9075000 atm

5 0
3 years ago
Density of a piece of wood that has a measurement of 24 cm3 and 768 g
Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 768 g

volume = 24 cm³

We have

density =  \frac{768}{24}  \\

We have the final answer as

<h3>32 g/cm³</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
An air sample contains 0.044% CO2? If the total pressure is 750 mm Hg. What is the partial pressure of CO2?2?
Aleksandr [31]
Partial pressure=mole fraction×Pt
x=0.044÷44(maolarmass of CO2)×Pt
x=0.044÷(44)2×Pt
x=5×10^-4×Pt
x=5×10^-4×Pt
where Pt:1atm=760mmHg
xatm=750mmHg
750×1÷760=0.99
now;5×10^-4×099=4.95×10^-4.
Pt=4.95×10^-4
8 0
3 years ago
Label the parts of the respiratory system.
Evgesh-ka [11]

Answer:

1. Nose

2. Mouth

3. Larynx

4. Lung

5. RIght Bronchi

6. Diaphragm

7. Pharynx

8. Trachea

9. Left Bronchi

10. Bronchioles

11. Avoli

Explanation:

8 0
3 years ago
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