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hram777 [196]
2 years ago
5

Read the given equation.

Chemistry
1 answer:
Law Incorporation [45]2 years ago
3 0
<h2>Answer:</h2>

<h3>From the equation it is evident that 2 moles of Sodium metal produces 1 mole of hydrogen gas.</h3><h3>At STP 1mole of any gas occupies a volume of 22.4 litres.</h3><h3>Therefore, 7.80 gives---(7.80x1)/22.4 moles = 0.3482 moles</h3><h3>Since the mole ratio of Sodium to hydrogen is 2:1, then the number of moles of sodium that reacted is given by the following expression.</h3><h3>(0.3482 * 2) / 1 moles which gives 0.6964 moles.</h3><h3>The atomic mass of sodium is 23 thus the mass of sodium that reacted is given by:</h3><h3>mass=no. of Monogram</h3><h3>0.6964 * 23 = 16.02 grams.</h3><h2>Explanation:</h2><h3>please mark me brainlist</h3>

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3 years ago
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7 0
2 years ago
Given that the ka for hocl is 3.5 × 10–8, calculate the k value for the reaction of hocl with oh–.
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Following reaction is involved in above system
HOCl(aq)  ↔  H+(aq) + OCl-<span>(aq)
</span>OCl-(aq) + H2O(l)  ↔ HOCl(aq) + OH-<span>(aq)
</span>
Now, if the system is obeys 1st order kinetics we have
K  = [OCl-][H+<span>]/[HOCl]   ............. (1)
</span>∴ [HOCl-] / [OCl-] = [H+] (1 / 3.0 * 10-8<span>)   ............. (2)
</span>
and now considering that system is obeying 2nd order kinetics, we have
K  = [OH-][HOCl-] / [OCl-] ................. (3<span>)
</span>Subs 2 in 3 we get
K = [OH-][H+] (1 / 3.0 * 10-8<span>)
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</span>∴K = 3.3 * 10<span>-7
</span>
Thus, correct answer is e i.e none of these
6 0
3 years ago
Read 2 more answers
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