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2 years ago

Read the given equation.

Chemistry

1 answer:

Law Incorporation [45]2 years ago

3 0

<h2>Answer:</h2>

<h3>From the equation it is evident that 2 moles of Sodium metal produces 1 mole of hydrogen gas.</h3><h3>At STP 1mole of any gas occupies a volume of 22.4 litres.</h3><h3>Therefore, 7.80 gives---(7.80x1)/22.4 moles = 0.3482 moles</h3><h3>Since the mole ratio of Sodium to hydrogen is 2:1, then the number of moles of sodium that reacted is given by the following expression.</h3><h3>(0.3482 * 2) / 1 moles which gives 0.6964 moles.</h3><h3>The atomic mass of sodium is 23 thus the mass of sodium that reacted is given by:</h3><h3>mass=no. of Monogram</h3><h3>0.6964 * 23 = 16.02 grams.</h3><h2>Explanation:</h2><h3>please mark me brainlist</h3>

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3 years ago

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3 years ago

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Which of the following is an irreversible physical change?

Yuliya22 [10]

Answer:

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4 years ago

g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu

scZoUnD [109]

Answer:

$CuCl_2$ is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

$CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2$

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

$\frac{1}{2}\times 0.500 mol=0.250 mol$ of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give :

$\frac{2}{2}\times 0.500 mol=0.500 mol$ of silver chloride

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3 years ago

Decide which element probably forms a compound with chlorine that has a chemical formula most and least similar to the chemical

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Strontium forms a compound with formula $SrCl_2$ in which strontium acts as a cation and chlorine acts as an anion. The formation of the compound is as shown in the image.

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4 years ago