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2 years ago

Read the given equation.

Chemistry

1 answer:

Law Incorporation [45]2 years ago

3 0

<h2>Answer:</h2>

<h3>From the equation it is evident that 2 moles of Sodium metal produces 1 mole of hydrogen gas.</h3><h3>At STP 1mole of any gas occupies a volume of 22.4 litres.</h3><h3>Therefore, 7.80 gives---(7.80x1)/22.4 moles = 0.3482 moles</h3><h3>Since the mole ratio of Sodium to hydrogen is 2:1, then the number of moles of sodium that reacted is given by the following expression.</h3><h3>(0.3482 * 2) / 1 moles which gives 0.6964 moles.</h3><h3>The atomic mass of sodium is 23 thus the mass of sodium that reacted is given by:</h3><h3>mass=no. of Monogram</h3><h3>0.6964 * 23 = 16.02 grams.</h3><h2>Explanation:</h2><h3>please mark me brainlist</h3>

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Answer:

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2 years ago

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3 years ago

If two electrically charged objects repel one another, which statement must be true? One object has more electrons, and the othe

mel-nik [20]

Answer:

The two objects have the same electric charge.

Explanation:

Electrically charged objects repel if they are both of the same charge, ie plus plus or minus minus.

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3 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

lina2011 [118]

First, write the chemical reaction a<span>nd balance it:

NBr3 + NaOH ---> N2 + NaBr + HOBr</span>

<span>2 NBr3 + 3 NaOH ---> N2 + 3 NaBr + 3 HOBr</span>

Then the theoretical proportion is 2 NBr3 : 3 NaOH

The reactants are in the proportion 40 NBr : 48 NaOH

From the theoretical proportion you can make [2 NBr3 / 3 NaOH] * 48 NaOH = 32 NaOH.

Given that you have more than 32 moles of NaOH, this is the excess reactant.

3 0

3 years ago

A student collects 300mL of hydrogen gas at 22°C and

pantera1 [17]

Answer: 2169.1K

Explanation:

Given that,

Original volume of hydrogen gas (V1) = 300mL

[Convert 300mL to liters

If 1000mL = 1L

300mL = 300/1000 = 0.3L]

Original temperature of hydrogen gas (T1) = 22°C

[Convert 22°C to Kelvin by adding 273

22°C + 273 = 295K]

Original pressure of hydrogen gas = 91.9 kPa

[Since new pressure is in atm, convert 91.9 kPa to atmosphere

If 101.325 kPa = 1 atm

91.9 kPa = 91.9/101.325 = 0.9069 atm]

New volume of hydrogen gas (V2) = 2L

New temperature of hydrogen gas (T2) = ?

New pressure of hydrogen gas (P2) = 1 atm

Since pressure, volume and temperature are given, apply the formula for the combined gas equation

(P1V1)/T1 = (P2V2)/T2

(0.9069 atm x 0.3L)/295K = (1 atm x 2L)/T2

0.272 atm•L / 295K = 2 atm•L / T2

To get the value of T2, cross multiply

0.272 atm•L x T2 = 2 atm•L x 295K

0.272 atm•L•T2 = 590 atm•L•K

Divide both sides by 0.272 atm•L

0.272 atm•L•T2/0.272 atm•L = 590 atm•L•K/0.272 atm•L

T2 = 590 atm•L•K / 0.272 atm•L

T2 = 2169.1K

Thus, the new temperature of the hydrogen gas is 2169.1K

8 0

3 years ago