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Kaylis [27]
2 years ago
10

What is the mass of an object that requires a force of 30 N to accelerate at 5 m/s2?

Physics
1 answer:
alexira [117]2 years ago
3 0

Answer:

6 Kg.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 30 N

Acceleration (a) = 5 m/s²

Mass (m) =?

Force (F) is defined as the product of mass (m) and acceleration (a). Mathematically, it can be expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can obtain the mass of the object as follow:

Force (F) = 30 N

Acceleration (a) = 5 m/s²

Mass (m) =?

F = ma

30 = m × 5

Divide both side by 5

m = 30 / 5

m = 6 Kg

Therefore, the mass of the object is 6 Kg

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A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
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Answer:

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Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

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So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

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g= \frac{GM}{r^2}
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r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m

And now we can use the previous equation to calculate the field strength at that altitude:
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