All categories

2 years ago

What is the mass of an object that requires a force of 30 N to accelerate at 5 m/s2?

Physics

1 answer:

alexira [117]2 years ago

3 0

Answer:

6 Kg.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 30 N

Acceleration (a) = 5 m/s²

Mass (m) =?

Force (F) is defined as the product of mass (m) and acceleration (a). Mathematically, it can be expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can obtain the mass of the object as follow:

Force (F) = 30 N

Acceleration (a) = 5 m/s²

Mass (m) =?

F = ma

30 = m × 5

Divide both side by 5

m = 30 / 5

m = 6 Kg

Therefore, the mass of the object is 6 Kg

You might be interested in

Help me please and thank you

katovenus [111]

Answer:

go to : www.planetresourses.com/test2.00/answers, ant type in that test name

Explanation:

yee

3 0

2 years ago

Mars has two moons. What does the orbital speed of these moons depend on?

Radda [10]

Answer:

their masses and their distances from Mars

Explanation:

Hope this helped

Also can u pls mark me brainliest

8 0

2 years ago

Oxygen has an atomic number of 8. What can you conclude from this fact?

Alja [10]

Answer:

The answer to your question is below

Explanation:

If Oxygen has an atomic number of 8, we can conclude that:

- If neutral, it has 8 protons and 8 electrons

- It has 8 neutrons and its atomic mass is 16 (A = 8 + 8)

- It must be located in the group VI A

- Its valence number must be 6

- Its Oxidation number is -2

7 0

2 years ago

What is a half-life?

Serggg [28]

Answer:

option D is correct

Explanation:

5 0

2 years ago

Read 2 more answers

You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f

Alborosie

Answer:

3.25 m

Explanation:

t = Time taken = 0.166 seconds

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration = 9.81 m/s²

s = 1 because meter stick is 1 meter in length

$s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{1-\frac{1}{2}\times 9.81\times 0.166^2}{0.166}\\\Rightarrow u=5.21\ m/s$

Here, the initial velocity of point B is calculated from the time which is given. This velocity will be the final velocity of the acorn which falling from point A.

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{5.21^2-0^2}{2\times 9.81}\\\Rightarrow s=1.38\ m$

The distance of the acorn from the ground is 1.87+1.38 = 3.25 m

4 0

2 years ago