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Kaylis [27]
2 years ago
10

What is the mass of an object that requires a force of 30 N to accelerate at 5 m/s2?

Physics
1 answer:
alexira [117]2 years ago
3 0

Answer:

6 Kg.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 30 N

Acceleration (a) = 5 m/s²

Mass (m) =?

Force (F) is defined as the product of mass (m) and acceleration (a). Mathematically, it can be expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can obtain the mass of the object as follow:

Force (F) = 30 N

Acceleration (a) = 5 m/s²

Mass (m) =?

F = ma

30 = m × 5

Divide both side by 5

m = 30 / 5

m = 6 Kg

Therefore, the mass of the object is 6 Kg

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Two concentric, coplanar, circular loops of wire of different diameter carry currents in the same direction. Describe the nature
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Answer:

Both will be attractive in nature.

Explanation:

In the given case, the direction of the magnetic field is same in both loops as the direction of the current is same in both loops. When two parallel straight wire carrying current in the same direction are brought close to each other, the force between them is attractive in nature. In the same way,  when two coplanar, circular and concentric loops of wire are carrying current in the same direction, the force between them is attractive in nature. It can be checked by using right hand thumb rule.

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2 years ago
Hai ô tô khởi hành cùng lúc từ A,B cách nhau 20 km chuyển động theo hướng từ A đến B vs vận tốc lần lượt là 60km/h và 40km/h
sdas [7]

Answer:

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s là dộ dài qduong

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Explanation:

6 0
2 years ago
A 55.0-g aluminum block initially at 27.5 degree C absorbs 725 J of heat. What is the final temperature of the aluminum? Express
andrew11 [14]

Answer:

Final temperature of the aluminum = 41.8 °C

Explanation:

We have the equation for energy

      E = mcΔT

Here m = 55 g = 0.055 kg

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E = 725 J

Substituting

     E = mcΔT

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Final temperature of the aluminum = 41.8 °C

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