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melamori03 [73]
3 years ago
12

A particle moves according to the equation x = 11t^2, where x is in meters and t is in seconds.

Physics
1 answer:
Savatey [412]3 years ago
4 0
We are given the equation:

<span>x = 11t^2
</span>
We use that equation to calculate for the distance traveled.
For (a)

At t=2.20 sec,    
                             x =53.24 meters

At t=2.95 sec,   
                             x =95.73 meters

Velocity = (95.73 meters - 53.24<span> meters) / (2.95 s - 2.20 s )  = 56.65 m/s

</span>For (b)

At t=2.20 sec,    
                             x =53.24 meters

At t=2.40 sec,   
                             x =63.36 meters

Velocity = (63.36 meters - 53.24<span> meters) / (2.40 s - 2.20 s )  = 50.6 m/s</span>
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Katena32 [7]

Answer:

1

 t_a  =  13.49 \  s

2

 The distance is   D = 55.2 \  m    

Explanation:

From the question we are told that

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    The maximum of  gazelle is  u =  76.5 \  km/h =  21.25 \  m/s

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Let  t_a denote the time which the cheetah catches the gazelle

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           v* t_a = d +  u* t_a

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=>          7.36 t_a = 99.3

=>         t_a  =  13.49 \  s

Now at t =  7.5 s  

             7.5 v = D+  7.5u

=>          28.61 * 7.5  = D +  21.25* 7.5

=>          7.36 *  7.5 =D

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