A 44,495 kg spacecraft is traveling through space with an initial speed of 1,290 m/s relative to Earth. A thruster fires for 27.
1 answer:
Answer:
The final momentum of the spacecraft is, p' = 57363368.4 kg m/s
Explanation:
Given data,
The mass of the spacecraft. m = 44495 kg
The initial speed of the spacecraft, u = 1290 m/s
The thruster fires for the time, t= 27.4 s
The continuous force exerted by the thruster, F = 1284 N
The initial momentum of the spacecraft, p = mu
p = 44495 x 1290
= 57398550 kg m/s
The final momentum of the spacecraft, p' = mv
According to newton's II law, the rate of change of momentum is equal to the force acting on the body.
p' = Ft + mu
= -1284 x 27.4 + 57398550
= 57363368.4 kg m/s
Hence, the final momentum of the spacecraft is, p' = 57363368.4 kg m/s
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