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Ghella [55]
3 years ago
7

What is projectile motion​

Physics
2 answers:
Rashid [163]3 years ago
8 0

Explanation:

the form of motio experienced by an object or particle that is project near the earth surface and moves along a curved path under the action of gravity only

hope this answer will help you

thankyou

MakcuM [25]3 years ago
7 0

<h2><u>Projectile</u><u> </u><u>motion</u><u>:</u></h2>

<em>If</em><em> </em><em>an</em><em> </em><em>object is given an initial velocity</em><em> </em><em>in any direction and then allowed</em><em> </em><em>to travel freely under gravity</em><em>, </em><em>it</em><em> </em><em>is</em><em> </em><em>called a projectile motion</em><em>. </em>

It is basically 3 types.

  1. horizontally projectile motion
  2. oblique projectile motion
  3. included plane projectile motion

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Answer:

C. 32.7%

Explanation:

% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest

6 0
3 years ago
Which of the following examples shows the greatest amount of biodiversity
Anna [14]

Answer:

A lake full of a larger variety of fish, frogs, and birds

3 0
3 years ago
The slope of a linear position graph tells us the blank of the object
sveta [45]

Answer:

velocity of the object

Explanation:

For an object moving at a constant acceleration, we would expect to see a position graph with a curved shape and a velocity graph with a straight shape.

6 0
3 years ago
A shell is shot with an initial velocity v with arrow0 of 18 m/s, at an angle of θ0 = 60° with the horizontal. At the top of the
BARSIC [14]

Answer:

D = 43 m

Explanation:

given,

initial velocity = 18 m/s

angle θ = 60°

total horizontal distance covered by the shell is

R = \dfrac{v_0^2sin 2\theta}{g}

applying conservation of momentum in horizontal direction

m v₀ cos θ = m₁v₁ + m₂ v₂

m v₀ cos θ = 0.5 m v₂

v₂ = 2 v₀ cos θ.

distance covered by the shell from point of explosion

R' = v t

  = (2 v_0 cos \theta) (\dfrac{v_0^2sin \theta}{g})

  =(2 \dfrac{v_0^2cos \theta sin \theta}{g})

  = \dfrac{v_0^2sin 2\theta}{g}

  = R

total distance traveled by the shell is

D = \dfrac{R}{2}+R'

   = 1.5 R

   = 1.5\dfrac{v_0^2sin 2\theta}{g}

D = 1.5\dfrac{18^2sin 2\times 60}{9.81}

   = 42.9 ≅ 43 m

D = 43 m

3 0
3 years ago
A 20 liter cylinder of helium at a pressure of 150 atm and a temperature of 27ÁC is used to fill a balloon at 1.00 atm and 37ÁC.
djyliett [7]

<u>Answer</u>

D) 3100 Liters


<u>Explanation</u>

To get the volume if the balloon you need to use the combined equation of the low of gases.

P₁V₁/T₁ = P₂V₂/T₂

(20×150)/(27+273) = (1×V₂)/(37+273)

3000/300 = V₂/310

10 = V₂/310

V₂ = 10 × 310

    = 3100 Liters


7 0
3 years ago
Read 2 more answers
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