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Ghella [55]
3 years ago
7

What is projectile motion​

Physics
2 answers:
Rashid [163]3 years ago
8 0

Explanation:

the form of motio experienced by an object or particle that is project near the earth surface and moves along a curved path under the action of gravity only

hope this answer will help you

thankyou

MakcuM [25]3 years ago
7 0

<h2><u>Projectile</u><u> </u><u>motion</u><u>:</u></h2>

<em>If</em><em> </em><em>an</em><em> </em><em>object is given an initial velocity</em><em> </em><em>in any direction and then allowed</em><em> </em><em>to travel freely under gravity</em><em>, </em><em>it</em><em> </em><em>is</em><em> </em><em>called a projectile motion</em><em>. </em>

It is basically 3 types.

  1. horizontally projectile motion
  2. oblique projectile motion
  3. included plane projectile motion

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A student of mass 60.0 kg, starting at rest, slides down a slide 20.0 m long, tilted at an angle of 30.0° with respect to the ho
cricket20 [7]

Answer:

Explanation:

Reaction force of inclined surface

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=60 x 9.8 x .866

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Force of kinetic friction

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b )

net force downwards = mgsinθ - μmgcosθ

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8 0
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A trailer truck with a 2000 [kg] cab and a 8000 [kg] trailer is traveling on a level road at 90 [km/hr].The brakes on the traile
NeX [460]

Answer:

a)   t = 19.6 s, b) fr = 1.274 10⁴ N

Explanation:

This is a Newton's second law problem

Y Axis

for the cabin

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        N₁ = W₁

for the trailer

        N₂- W₂ = 0

        N₂ = W₂

X axis

for the cabin plus trailer, where friction is only in the cabin

         fr = (m₁ + m₂) a

the friction force equation is

        fr = μ N

we substitute

       μ N₁ = (m₁ + m₂) a

        μ m₁ g = (m₁ + m₂) a

        a = μ g    \frac{m_1}{m_1 + m_2}

         

let's calculate

         a = 0.65 9.8    \frac{2000}{2000+8000}

         a = 1,274 m / s²

a) to find the stopping distance we can use kinematics

         Let's slow down the sI system

         v₀ = 90 km / h (1000 m / 1km) (1h / 3600s) = 25 m / s

         v = v₀ - a t

when it is stopped its speed is zero

           0 = v₀ - at

           t = v₀ / a

           t = 25 / 1.274

           t = 19.6 s

b) the friction force is

           fr = 0.65 2000 9.8

          fr = 1.274 10⁴ N

This is the braking force and also the forces that couple the cars.

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