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4 years ago

Which statements about Earth’s core help explain Earth’s magnetic field? Check all that apply.

Physics

2 answers:

blsea [12.9K]4 years ago

6 0

Answer: The outer core is liquid and moving.

Earth’s core is composed of iron and nickel.

Explanation:

A magnetic field is produced by a magnetic material such as Iron, Cobalt or Nickel. Magnetic field are magnetic lines of force i.e. the region which experiences magnetic force. Earth acts as a huge bar magnet and has magnetic field around it due to which we are shielded by solar particles and experience phenomenon such as Auroras.

The earth acts as bar magnet due to presence of iron and nickel in molten form in its core. The outer core is liquid and moves generating a magnetic field. Thus, the correct options are:

The outer core is liquid and moving.

Earth’s core is composed of iron and nickel.

Stella [2.4K]4 years ago

5 0

All the statements can be used to explain about Earth's magnetic field.

Earth's magnetic field is almost same to that of the bar magnet. The magnetic field of the earth occurs from its core. It has an inner core which is solid in nature. in the outer core, there is a motion of the liquid due to heat flow from the inner core to the core mantle boundary which proves that the outer core is liquid and moving. The Earth's core consists of iron and nickel as the Eddy currents in the iron and nickel liquid helps generating the Earth's magnetic field.

Hence, all the three statements are true and can be used to explain the Earth's magnetic field.

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2 years ago

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3 years ago

How much work did the movers do (horizontally) pushing a 43.0-kg crate 10.4 m across a rough floor without acceleration, if the

Ilia_Sergeevich [38]

The crate is in equilibrium. Newton's second law gives

∑ F (vertical) = n - mg = 0

∑ F (horizontal) = p - f = 0

where

• n = magnitude of the normal force

• mg = weight of the crate

• p = mag. of push exerted by movers

• f = mag. of kinetic friciton, with f = 0.60n

It follows that

p = f = 0.60mg = 0.60 (43.0 kg) g = 252.84 N

so that the movers perform

W = p (10.4 m) ≈ 2600 J

of work on the crate. (The total work done on the crate, on the other hand, is zero because the net force on the crate is zero.)

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3 years ago

The speed of a particle moving in a circle 2.0 m in radius increases at the constant rate of 4.4 m/s2. At an instant when the ma

Law Incorporation [45]

Answer:

The speed of the particle is 2.86 m/s

Explanation:

Given;

radius of the circular path, r = 2.0 m

tangential acceleration, $a_t$ = 4.4 m/s²

total magnitude of the acceleration, a = 6.0 m/s²

Total acceleration is the vector sum of tangential acceleration and radial acceleration

$a = \sqrt{a_c^2 + a_t^2}\\\\$

where;

$a_c$ is the radial acceleration

$a = \sqrt{a_c^2 + a_t^2}\\\\a^2 = a_c^2 + a_t^2\\\\a_c^2 = a^2 -a_t^2\\\\a_c = \sqrt{a^2 -a_t^2}\\\\a_c = \sqrt{6.0^2 -4.4^2}\\\\a_c = \sqrt{16.64}\\\\a_c = 4.08 \ m/s^2$

The radial acceleration relates to speed of particle in the following equations;

$a_c = \frac{v^2}{r}$

where;

v is the speed of the particle

$v^2 = a_c r\\\\v= \sqrt{a_c r} \\\\v = \sqrt{4.08 *2}\\\\v = 2.86 \ m/s$

Therefore, the speed of the particle is 2.86 m/s

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4 years ago