Question

Pls help. This is about heat. I got the answer, just need the working

Answer 1

Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C  from 20 C

  this will take   .20 kg *    390 j /kg-C   *  80 C = 6240 j

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take    

    .50 kg * 4182 j/kg-C  * 80 = 167,280 j

AND you have to add enough heat to boil off  .03 kg of water:

   .03 kg * (2260000 j/kg-C )  = 67,800 j

Power = joules / sec =  (6240 + 167280 + 67800) / 274.8 = 878 watts

Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....