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boyakko [2]
3 years ago
12

Which of the following are you not likely to see on a graph?​

Physics
1 answer:
Crazy boy [7]3 years ago
8 0

Answer:

What are the following?

Things you do see on a graph:

Points, intercepts, x-axis, y-axis, x-coordinate, y-coordinate, 4 quarters

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An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p
igor_vitrenko [27]

Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

Given:

Distance from the wire to the field point r = 2.83 \times 10^{-2} m

Speed of electron v = 35.5 \%c

Current I = 17.7 A

For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

  F = ma

Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

7 0
2 years ago
When you whirl a can at the end of a string in a circular path, what is the direction of the force that acts on the can
andreyandreev [35.5K]

Answer:

Toward the centre of the circular path

Explanation:

The can is moved in a circular path: this means that it is moving by circular motion (uniform circular motion if its tangential speed is constant).

In order to keep a circular motion, an object must have a force that pushes it towards the centre of the circular trajectory: this force is called centripetal force, and its magnitude is given by

F=m\frac{v^2}{r}

where m is the mass of the object, v its tangential speed, r the radius of the trajectory. This force always points towards the centre of the circular path.

3 0
3 years ago
Two parallel conducting plates are separated by 9.2 cm, and one of them is taken to be at a potential of zero volts.What is the
True [87]

Answer:

E=54V/cm

\Delta V=496.8V between the plates.

Explanation:

The equation for change of voltage between two points separated a distance d inside parallel conducting plates (<em>which have between them constant electric field</em>) is:

\Delta V=Ed

So to calculate our electric field strength we use the fact that the potential 8.8 cm from the zero volt plate is 475 V:

E=\frac{\Delta V}{d}=\frac{475 V}{8.8cm}=54V/cm

And we use the fact that the plates are 9.2cm apart to calculate the voltage between them:

\Delta V=Ed=(54V/cm)(9.2cm)=496.8V

8 0
3 years ago
How are the different firework shapes produced
AleksAgata [21]

To create the shapes, stars are arranged on a piece of cardboard in the desired configuration. If the stars are placed in a smiley face pattern on the cardboard, for example, they will explode into a smiley face in the sky. In fact, you may see several smiley faces in the sky at one time.

Your Welcome

8 0
3 years ago
A crate is being lifted into a truck. If it is moved with a 2470 N force and 4850 J of work is done, then how far is the crate b
olchik [2.2K]

Answer:1.96m

Explanation:

Work=4850J

Force=2470N

Distance =work ➗ force

Distance =4850 ➗ 2470

Distance =1.96m

7 0
3 years ago
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