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3 years ago

Terry is convinced that heating peanut butter will increase its mass so that it covers more bread. Is he correct?

1 answer:

4 0

The answer would be b. Heating the peanut putter will just make it expand but it will still be the same mass unless you add more

You might be interested in

What is the correct answer?

damaskus [11]

Answer:

96 million of dollars

Explanation:

p=-6x^3+72x

p=-6(2)^3+72(2)

p=-6(8)+144

p=-48+144

p=96

8 0

3 years ago

F each fission reaction in a nuclear reactor emits three neutrons, how many neutrons are produced from three fission reactions?

IrinaK [193]

The Three fission reactions will produce nine neutrons

<h3>Meaning of Fission</h3>

Fission can be defined as a nuclear process that involves the breaking of a whole nuclear matter into smaller bits.

In a fission reaction, the matter is broken down into simpler bits.

In conclusion, The Three fission reactions will produce nine neutrons

Learn more about fission:brainly.com/question/3992688

#SPj1

8 0

2 years ago

To balance a chemical equation we use______. <br> -coefficients <br> -subscripts

Vitek1552 [10]

Answer:

Coefficients

Explanation:

Coefficients are used to balance chemical equations.
According to the law of conservation of mass, the mass of the reactants in a chemical equation should be equivalent to the mass of the products.
The conservation of mass is achieved in chemical equations is achieved through balancing chemical equations.
<em><u>Balancing chemical equations is a try and error of putting appropriate coefficients to the reactants or products to ensure that the number of atoms of each element are equal on the side of the reactants and that of products. </u></em>

3 0

3 years ago

Sharon throws a 0.20 Kg with an acceleration of 10 m/s/s.

OlgaM077 [116]

Force=A×M
10m/s×0.20kg
=2Newton

4 0

3 years ago

A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar

notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2> $\omega = 0.23 rad/s$ </h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

$L_i = L_f$

now we can say

$m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega$

so we will have

$0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega$

$\omega = 0.23 rad/s$

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0

3 years ago