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igor_vitrenko [27]
2 years ago
10

Terry is convinced that heating peanut butter will increase its mass so that it covers more bread. Is he correct?

Physics
1 answer:
aleksandrvk [35]2 years ago
4 0
The answer would be b. Heating the peanut putter will just make it expand but it will still be the same mass unless you add more

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You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.90 mA when a sin
faust18 [17]

Answer:

Frequency required will be 2421.127 kHz

Explanation:

We have given inductance L=0.450H=0.45\times 10^{-3}H

Current in the inductor i=1.90mA=1.90\times 10^{-3}A

Voltage v = 13 volt

Inductive reactance of the circuit X_l=\frac{v}{i}

X_l=\frac{13}{1.9\times 10^{-3}}=6842.10ohm

We know that

X_l=\omega L=2\pi fL

2\times 3.14\times  f\times 0.45\times 10^{-3}=6842.10

f = 2421.127 kHz

6 0
3 years ago
microwave ovens rotate at a rate of about 6.3 rev/min. what is this in revolutions per second? (you do not need to enter any uni
levacccp [35]

The microwave ovens rotate at a rate of about 0.105 rev/s.

The microwave rotation is the number of revolutions in a unit of time. To change the unit for angular velocity, assume that the quantity is multiplied by the unit it has. Then change to the desired units. The angular velocity is denoted by ω and has a magnitude of 6.3 rev/min.

ω = 6.3 rev/min

\omega = 6.3 \times \frac{1 \: rev}{1 \: min}

  • 1 minute = 60 seconds
  • The revolution unit didn't change

\omega = 6.3 \times \frac{1 \: rev}{60 \: seconds}

\omega = \frac{6.3 \: rev}{60 \: seconds}

ω = 0.105 rev/s

Learn more about Angular velocity here: brainly.com/question/29344944

#SPJ4

7 0
1 year ago
"A short-wave radio antenna is supported by two guy wires, 150 ft and 170 ft long. Each wire is attached to the top of the anten
Nonamiya [84]

Answer:

The anchor points are 78.37 ft and 111.99 ft

Explanation:

If you look at the attached (Fig 1) you will find that the union of antenna and its guy wires forms two right triangles. To solve problems that involve this kind of triangles, you can apply trigonometric functions (sine, cosine, etc) and Pythagoras Theorem. Trigonometric functions states the relation between angles, sides and hypotenuse of a right triangle. If you look Fig2, considering α angle, "b" is the opposite side, "a" the adjacent side and "c" the hypotenuse. Then

a) Sine (α) = b/c it means opposite side/hypotenuse

b) Cosine (α)= a/c, it means adjacent side/hypotenuse

c) Tangent (α) = b/a opposite side/adjacent side.

Pythagoras theorem states that if you called "a" and "b", the sides of the right triangle, and "c" the hypotenuse, then:

                                      a² + b² = c²    

As the problem states the lengths 150 ft and 170 ft represents the value of the hypotenuse of each triangle and 65° is one of the angles of the triangle with 150 ft hypotenuse. So you can solve this using sin (65°) to find the height of the antenna (h) and then the two distances (x and y,).

Sine (65°) = h/ 150 ft ⇒ Sine (65°) x 150ft = h ⇒ h = 127.9 ft.

To find x : Cosine (65°) = x/ 150 ft ⇒ Cosine (65°) x 150 ft = x

⇒ x = 78.37 ft.

And finally, to find y we can apply Pythagoras theorem

(170 ft)² = (127.9 ft)² + y² ⇒ y² = (170 ft)² - (127.9 ft)² ⇒ y = 111.99 ft

Summarizing, the anchor points are 78.37 ft and 111.99 ft

4 0
3 years ago
I need help on number 6 pls due today
Natalija [7]

Explanation:

Graph A matches description 4 because the car is coming back.

Graph B matches description 3 because the speed of the car is decreasing.

Graph C matches the description 2 because the car is traveling at a constant rate.

Graph D matches the description 1 because the car is stopped.

3 0
2 years ago
When a pitcher throws a baseball, it reaches a top speed of 39 m/s. if the
Aliun [14]

From the calculation, the acceleration of the body is 26m/s^2.

<h3>What is motion under gravity?</h3>

When an object is thrown up or down, the motion of the body is influenced by the gravitational pull on the body.

Now;

Given that;

v = 39 m/s

t = 1.5 s

u = 0 m/s

a = ?

v = u + at

v = at

a = v/t

a = 39 m/s/1.5 s

a = 26m/s^2

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

4 0
2 years ago
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