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Scorpion4ik [409]
3 years ago
12

'Suppose your hand moves upward by 0.50m while you are throwing the ball. The ball leaves your hand with an upward velocity of 2

0.0 m/s. Find the magnitude of the force (assumed constant) that your hand exerts on the ball. Ignore air resistance.' Now my question is not 'What is the magnitude' but rather: why did I get (roughly) the same answer using F=ma when you were supposed to use the total mechanical energy (W+K1+U1=K2+U2). So I'm more confused about how the 2 formulas are 'related', what the force actually represents in both, when to use what and if there is an actual difference.

Physics
1 answer:
Sholpan [36]3 years ago
5 0

The formula F = ma is used when the statement of second law of motion is applied to the problem. If the statement is applied to the problem, The fomula willbe used. If not, use the formula W +  K_{1} +  U_{1} =  K_{2} +  U_{2}

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Imagina que haces girar tu brazo extendido, ¿qué parte tendrá mayor velocidad angular, el codo o la mano?
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Answer:

the angular velocity is the same for both.

Explanation:

Angular velocity is defined by the change in angle between time

          w = Δθ /Δt

As the arm and elbow are on the same axis the two rotate the same angles, therefore the angular velocity is the same for both.

This does not happen with linear speed

          v = w r

therefore as the hand has a greater radius its greater linear speed

Traalate

La velocidad angular es definida por el cambio del angulo entre el tiempo

w= Δθ/ΔDt

como el brazo y el codo están en el mismo eje los dos girar los mismo ángulos, por lo tanto la velocidad angular es la misma para los dos.

Esto no pasa con la velocidad lineal

          v = w r

por lo tanto como la mano tiene un radio mayor su velocidad lineales mayor

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