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Scorpion4ik [409]
2 years ago
12

'Suppose your hand moves upward by 0.50m while you are throwing the ball. The ball leaves your hand with an upward velocity of 2

0.0 m/s. Find the magnitude of the force (assumed constant) that your hand exerts on the ball. Ignore air resistance.' Now my question is not 'What is the magnitude' but rather: why did I get (roughly) the same answer using F=ma when you were supposed to use the total mechanical energy (W+K1+U1=K2+U2). So I'm more confused about how the 2 formulas are 'related', what the force actually represents in both, when to use what and if there is an actual difference.

Physics
1 answer:
Sholpan [36]2 years ago
5 0

The formula F = ma is used when the statement of second law of motion is applied to the problem. If the statement is applied to the problem, The fomula willbe used. If not, use the formula W +  K_{1} +  U_{1} =  K_{2} +  U_{2}

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If it freezes at -58°C, hence the melting point is also <span>-58°C.</span>
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Q1: An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical
gizmo_the_mogwai [7]

Answer:

a) F= 0,19  [N]   according to problem statement

b) F = 0,19*10⁹ [N]  using the right value of K

Explanation:

The force between two electric charges is according to Coulomb´s law is:

F = K * q₁*q₂ / d²    where  q₁  and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant  K = 8,988100*10⁹ N.m²/C². The problem establishes to use        K = 8,988100 N.m²/C².

NOTE: To value of is :  K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹

Then:

F = 8,988100 * 1,2* 0,36 / (4,5)²     [ N*m²/C² ] * [ C*C*/m²]

F = 3,882859/ 20,25  [N]

F= 0,19  [N]

The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies

4 0
3 years ago
A child on a swing falls a height of 1m. What speed will the child reach?
kirill [66]

Answer:v=4.42\ m/s

Explanation:

Given

Child falls a height of h=1\ m

Applying conservation of energy  we can write

Loss in Potential energy=Gain in kinetic energy

mgh=\frac{1}{2}mv^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 1}

v=\sqrt{19.6}

v=4.42\ m/s

Thus child reaches a velocity of 4.42 m/s

7 0
3 years ago
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