Some sources say : One cycle = consumption of 3 CO2
Some other sources say : One cycle = consumption of 1 CO2 [This is the more frequent definition]
Anyway, the important point is that for one molecule of glucose [or 2 molecules of G3p], 6 CO2, 18 ATP, and 12 NADPH are used. I would say we need 6* cycles for one molecule of glucose [based on the more frequent definition]'
I hope this helps
Answer:
in t seconds, Car A sweep out t radian { i.e θ = t radian }
Explanation:
Given the data in the question;
4 toy racecars are racing along a circular race track.
They all start at 3 o'clock position and moved CCW
Car A is constantly 2 feet from the center of the race track and moves at a constant speed
so maximum distance from the center = 2 ft
The angle Car A sweeps out increases at a constant rate of 1 radian per second.
Rate of change of angle = dθ/dt = 1
Now,
since dθ/dt = 1
Hence θ = t + C
where C is the constant of integration
so at t = 0, θ = 0, the value of C will be 0.
Hence, θ = t radian
Therefore, in t seconds, Car A sweep out t radian { i.e θ = t radian }
C) 6h i’m not that great at math but that’s what i got hope it helps!!
The force on an object use Socratic glad to help ..
Answer:
The specific heat of a substance (per unit of mass) has dimension L. T. Θ−1, or (L/T)2/Θ. Therefore, the SI unit J/K/kg is equivalent to metre squared per second squared per kelvin (m2 K−1 s−2).
