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never [62]
3 years ago
11

Can somebody help me wit dis?

Chemistry
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

it is D

Explanation:

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Please just look up stuff about helium and put it in your own words 3-5 parts ill give brainly
andreyandreev [35.5K]

Answer:

Element Name & Symbol: Helium, He

Element Family : Noble Gasses

Atomic Number: 2

Atomic Mass: 4

Answer from Gauthmath

6 0
3 years ago
Read 2 more answers
Suppose the reaction between nitrogen and hydrogen was run according to the amounts presented in Part A, and the temperature and
andrew11 [14]

Explanation:

Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.

This means that, for N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}

 moles of N_{2} + moles of H_{2} = 0.908 mol

Since, 2 moles of N_{2} = 2 \times 0.227 = 0.454 mol

As it is known that the ideal gas equation  is PV = nRT

And, as the temperature and volume were kept constant, so we can write

        \frac{P(_in)}{n_(in)} = \frac{P_(final)}{n_(final)}

          \frac{10.4}{0.908} = \frac{P_(final)}{0.454
}

       P_(final) = 10.4 \times \frac{0.454}{0.908}

                            = 5.2 atm

Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.

7 0
3 years ago
For the reaction
Pepsi [2]

Answer:

Mass of Na₂CrO₄ =  5.75 g

Explanation:

First of all we will write the balance chemical equation.

2AgNO₃ + Na₂CrO₄     →    Ag₂CrO₄  +  2NaNO₃

Now we will calculate the moles of AgNO₃.

Number of moles = mass / molar mass

Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 =  169.87 g/mol

Number of moles = mass / molar mass

Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol

Now we will compare the moles of AgNO₃ and  Na₂CrO₄ from balance chemical equation.

                        AgNO₃    :     Na₂CrO₄

                          2            :           1

                          0.071     :           1/2× 0.071 = 0.0355

Now we will calculate the mass of Na₂CrO₄.

Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol

Mass of Na₂CrO₄ = number of moles  ×  molar mass

Mass of Na₂CrO₄ =  0.0355 mol ×  162 g/mol

Mass of Na₂CrO₄ =  5.75 g

3 0
3 years ago
When 1.5 mol calcium nitrate dissolves in water, how many moles of ions should be present in solution?
____ [38]

Answer:

1.5 moles of Ca²⁺ and 3 moles of NO₃⁻

Explanation:

This is the dissociation:

Ca(NO₃)₂  →  Ca²⁺  +  2NO₃⁻

1.5 moles of salt will have the same moles of ion Ca²⁺ and the double of moles, of nitrate according to the equation.

Therefore will be 1.5 moles of Ca²⁺ and 3 moles of NO₃⁻

5 0
3 years ago
Diol oxidation without C-C bond breakage ....which products are formed??
babunello [35]
If its oxidised, water and carbon dioxide is formed.
4 0
3 years ago
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