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Elena-2011 [213]
3 years ago
6

An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel

s 1.11 m. What is the speed of the airplane at the end of the second second?
Physics
1 answer:
Licemer1 [7]3 years ago
3 0

Answer:

v=4.44\frac{m}{s}

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero)  and accelerates at a constant rate, position can be described like this: x=v_{0}t +\frac{1}{2} at^{2} where x is the position, t is the time a is the acceleration and v_{0} is initial velocity. In this way acceleration can be found. a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }.

Now we are able to found velocity at any time with the formula: v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}

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0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

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