Answer:
$ 1.1
Explanation:
From the question given above, the following data were obtained:
Cost per kWh = $ 0.1
Current (I) = 10 A
Voltage (V) = 220 V
Time (t) = 5 h
Cost of operation =?
Next, we shall determine the power the electric oven. This can be obtained as follow:
Current (I) = 10 A
Voltage = 220 V
Power (P) =?
P = IV
P = 10 × 220
P = 2200 W
Next, we shall convert 2200 W to KW. This can be obtained as follow:
1000 W = 1 KW
Therefore,
2200 W = 2200 W × 1 KW / 1000 W
2200 W = 2.2 KW
Thus, 2200 W is equivalent to 2.2 KW.
Next, we shall determine the energy consumed by the electric oven. This can be obtained as follow:
Power (P) = 2.2 KW
Time (t) = 5 h
Energy (E) =?
E = Pt
E = 2.2 × 5
E = 11 KWh
Finally, we shall determine the cost of operation. This can be obtained as follow:
1 KWh cost $ 0.1
Therefore,
11 KWh will cost = 11 × 0.1
11 KWh will cost = $ 1.1
Therefore, the cost of operating the electric oven is $ 1.1
The volume of the column is
(π) · (r²) · (length) =
(π) · (0.19 meter)² · (2.6 meters) =
(π) · (0.036 m²) · (2.6 m) =
0.294 m³ .
The density is 2,450 kg/m³ (VERY very dense, heavy concrete)
so the weight of the column is (mass)·(gravity) or
(density) · (volume) · (gravity) =
(2,450 kg/m³) · (0.294 m³) · (9.81 m/s²) =
(2,450 · 0.294 · 9.81) (kg · m³· m) / (m³ · s²) =
7,066 kg-m/s² = 7,066 Newtons .
But 9.81 Newtons = 2.20462 pounds on Earth (the weight of 1 kilogram of mass), so we have
(7,066 N) · (2.205 pound/9.81 N) =
(7,066 · 2.205 / 9.81) pounds =
1,588 pounds .
Answer:
the height of the image ÷ by the height of the object.
Explanation:
Answer:
1.77 m/s
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')............................ Equation 1
Where m = mass of the bullet, m' = mass of the block, u = initial velocity of the bullet, u' = initial velocity of the block, V = Velocity of the bullet-wood combination immediately after collision
make V the subject of the equation
V = (mu+m'u')/(m+m').................. Equation 2
Given: m = 0.04 kg, m' = 6.96 kg, u = 310 m/s, u' = 0 m/s (stationary)
Substitute into equation 2
V = (0.04×310+6.96×0)/(0.04+6.96)
V = 12.4/7
V = 1.77 m/s
Hence the speed, in m/s, of the bullet-plus-wood combination immediately after the collision is 1.77 m/s
