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alukav5142 [94]
4 years ago
14

Which step is not included in carbon cycle

Chemistry
1 answer:
DaniilM [7]4 years ago
6 0

Your answer would be Transpiration

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Which is the best metal to use in an alloy to increase its electrical conductivity?
denpristay [2]

Answer:

Its Silver!

Explanation:

I took a quiz, and i got it right!

7 0
4 years ago
Greg and Shawn are studying for a physical science test. Greg thinks that the kinetic energy of an object depends on the height
Ludmilka [50]
It should be mass and speed so they are both incorrect because the height doesn’t mean much, but what matters is how heavy the object is, and how fast it’s going to go.
4 0
3 years ago
The common titanium alloy known as T-64 has a composition of 90 weight% titanium 6 wt% aluminum and 4 wt% vanadium. Calculate th
Anna007 [38]

Explanation:

Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.

Mass of titanium = 90 g

Moles of titanium = \frac{90 g}{47.87 g/mol}=1.8800 mol

Total number of atoms of titanium ,a_t=1.8800 mol\times N_A

Mass of aluminum = 6 g

Moles of aluminium = \frac{6 g}{26.98 g/mol}=0.2223 mol

Total number of atoms of aluminium,a_a=0.2223 mol\times N_A

Mass of vanadium  = 4 g

Moles of vanadium= \frac{4 g}{50.94 g/mol}=0.0785 mol

Total number of atoms of vanadiuma_v=0.0785 mol\times N_A

Total number of atoms in an alloy = a_t+a_a+a_v

Atomic percentage:

Atomic\%=\frac{\text{total atoms of element}}{\text{Total atoms in alloy}}\times 100

Atomic percentage of titanium:

:\frac{a_t}{a_t+a_a+a_v}\times 100=\frac{1.8800 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=86.20\%

Atomic percentage of Aluminium:

:\frac{a_a}{a_t+a_a+a_v}\times 100=\frac{0.2223 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=10.19\%

Atomic percentage of vanadium

:\frac{a_v}{a_t+a_a+a_v}\times 100=\frac{0.0785 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=3.59\%

6 0
4 years ago
Select the correct answer. What is the enthalpy for the reaction represented in the following energy diagram? A. +200 kJ B. +350
Stella [2.4K]

Answer:

Option C. +150KJ

Explanation:

Data obtained from the question include:

Heat of reactant (Hr) = 200KJ

Heat of product (Hp) = 350KJ

Change in enthalphy (ΔH) =..?

The enthalphy of the reaction can be obtained as follow:

Change in enthalphy (ΔH) = Heat of reactant (Hp) – Heat of reactant (Hr)

ΔH = Hp – Hr

ΔH = 350 – 200

ΔH = +150KJ

Therefore, the enthalphy for the reaction above is +150KJ

6 0
3 years ago
The point at which a substance is at complete equilibrium is called? User: a hydrogen bond is a special form of what type of bon
Leto [7]
I don't know what the answer to your first question is. All of my teachers have only called it the equilibrium point.  However for your second question, a hydrogen bond is a special type of dipole-dipole attraction.  Only oxygen, nitrogen, and fluorine are able to make them when bonded with hydrogen.  Hydrogen bonding is what makes water have such a high boiling point considering how light the molecule is.<span />
4 0
3 years ago
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