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alukav5142 [94]
3 years ago
14

Which step is not included in carbon cycle

Chemistry
1 answer:
DaniilM [7]3 years ago
6 0

Your answer would be Transpiration

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Neon lamps, is composed of 90.483% of 20ne, 0.271% of 21ne, and 9.253% of 22ne. the 20ne atoms have a mass of 19.992 u, 21ne ato
WITCHER [35]

20.181 u

The average atomic mass of Ne is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,  

Avg. at. mass

= (0.904 83× 19.992 u) + (0.002 71 × 20.994) + (0.092 53× 21.991 u)

= 18.0894 u + 0.0569 u  + 2.0348 u = 20.181 u

8 0
3 years ago
Inside a room, the air is often warmer near the ceiling then near the floor. Which of the following accounts for this difference
Vanyuwa [196]
The correct answer is C. convection
4 0
3 years ago
The partial pressure of hellium gas in a gaseous mixture of hellium and hydrogen is<br>​
RUDIKE [14]

Answer:

The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

Hope this Helps (✿◡‿◡)

8 0
3 years ago
What is the chemical formula and net ionic equations for all three solutions.
timofeeve [1]

Answer:

See answer below

Explanation:

As you are asking for chemical formula and ionic equation, then, I will assume that after the station #4 below, are the solutions you are requiring.

You are also not specifing if you want for example, result of solution 1 + solution 3. If you need that, please post that on another question.

Now for the chemical formula, you need to identify the elements in all 3 solutions, and also the type of compound.

<u>1. Solution 2 Potassium Chloride: </u>

In this case we have Potassium on one side, and Chlorine on the other side, the symbol for those are K and Cl. As Potassium have the +1 oxidation state, cause is the only one that it can have, when it's next to an halide like chlorine or bromine, it will form a binary salt. The halides, usually work with the lowest oxydation state. In the case of Chlorine it will be -1, so, the formula will be:

KCl

And the net ionic equation will be the chemical equation that shows how the charges and atoms are balanced. In this case it would be:

K⁺ + Cl⁻ ------> KCl

<u>2. Solution 1 Copper(II) sulfate: </u>

In this case we have a tertiary salt, The copper's symbol is Cu, and is working with it oxydation state +2. Sulfate is an anion and it's formula is SO₄ and works with oxydation state -2 instead.

The chemical formula and ionic equation will be:  

Copper(II) sulfate: CuSO₄

And the net equation:

Copper sulfate: Cu²⁺ + SO₄²⁻ -------> CuSO₄

<u>3. Solution 3 Sodium hydroxide:</u>

In this case, we have a compound that it's usually used in acid base reactions. This is a strong base or hydroxide, and we have the element of Sodium (Na) with the oxydation state +1, is the only one it can have, and for the other side we have the oxydrile anion OH, and together is working with the oxydation state -1. So the chemical formula will be:

NaOH

And the net ionic equation:

Na⁺ + OH⁻ -------> NaOH

Hope this helps

4 0
3 years ago
Draw the correct structure(s) for (2R,3S)‑2,3‑dibromobutane. Show stereochemistry clearly. To ensure proper grading, explicitly
velikii [3]

Answer:

b. cannot exist in optically active form

Explanation:

Stereochemistry is a branch of chemistry that involves the spatial arrangement of the atoms of molecules and studies how this affects the physical and chemical properties of such species.

The correct structure for (2R,3S)‑2,3‑dibromobutane can be seen in the image attached below. Since the compound is a meso compound due to the plane of symmetry. Thus, the compound is achiral. i.e. Compounds that are superimposable on its mirror image. The plane of symmetry is vertical inclined at 90°(i.e. perpendicular) to the page thus goes via the middle of the molecule.

6 0
3 years ago
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