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Alex73 [517]
3 years ago
8

A boy is pulling a toy wagon through a neighborhood at a speed of 0.75 m/s. A caterpillar in the wagon is crawling toward the re

ar of the wagon at a rate of 2.0 cm/s. What is the caterpillar’s velocity relative to the ground?
Physics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

0.73 m/s in the forward direction

Explanation:

The caterpillar's velocity relative to the ground is given by:

v' = v_w + v

where

v_w is the velocity of the wagon with respect to the ground

v is the velocity of the caterpillar in the wagon's reference frame

In this situation we have

v_w = +0.75 m/s

v=-2.0 cm/s = -0.02 m/s where the negative sign is due to the fact that the caterpillar is moving backward

Substituting,

v'=+0.75-0.02=+0.73 m/s

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Two carts collide on a level, friction-less track. Cart A has a mass of 200 g and is initially stationary. Cart B has a mass of
Hatshy [7]
Convert 200 grams and 100 grams to 2kg and 1kg respectively 
momentum = mass x velocity 
momentum = 1 x 2 
initial momentum = 2 kg m/s
second scenario, cart b is moving -.5 m/s
momentum = mass x velocity
momentum = 1 x -.5
final momentum = -.5 kg m/s

momentum has to be the same in both scenarios so the 2 kg truck has to have a momentum of 2.5 kg m/s to push the total momentum of the second scenario to be 2 kg m/s like the first scenario

2.5 = 2 x velocity

velocity of cart a after the collision = 1.25 m/s

3 0
3 years ago
Which of the following best explains why mutations cannot cause evolution?
il63 [147K]
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4 0
4 years ago
What is the resistance at 20°C of a 2.0-meter length of tungsten wire with a cross-sectional area of 7.9 10^-7
Bad White [126]

Answer:

1.4 * 10 ^-1 Ω

Explanation:

Hi,

For this question, we gotta use the formula

R = pL/A

p = The resistivity of your material at 20°C

L = length of the wire

A = cross-sectional area

The resistivity of tungsten is 5.60 * 10^-8 at 20°C

By plugging the values, we get:

R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω

8 0
3 years ago
A frictionless inclined plane is 6 m long and rests on a wall that is 2 m high.
tresset_1 [31]

Answer:

The force needed to push a block of ice is 100 N.

Explanation:

It is given that,

Length of the friction less plane, l = 6 m

Height of the wall, h = 2 m

Weight of the block of ice, W = 300 N

The length of the inclined plane and the height of the wall act as hypotenuse and the perpendicular of the right angled triangle. Using trigonometry to find the angle as :

sin\theta=\dfrac{P}{H}

sin\theta=\dfrac{2}{6}

sin\theta=\dfrac{1}{3}

Force needed to push a block of ice weighing 300 N up the plane is equal to the horizontal component of the force as :

F_x=F\ sin\theta

F_x=300\times \dfrac{1}{3}

F_x=100\ N

So, the force needed to push a block of ice is 100 N. Hence, this is the required solution.

4 0
4 years ago
What happens to the current in a circuit if the resistance in the circuit is increased
8_murik_8 [283]

Answer:

Current Flow and Ohm's Law

Ohm's law is the most important, basic law of electricity. It defines the relationship between the three fundamental electrical quantities: current, voltage, and resistance. When a voltage is applied to a circuit containing only resistive elements (i.e. no coils), current flows according to Ohm's Law, which is shown below.

I = V / R

Where:

I =

Electrical Current (Amperes)

V =

Voltage (Voltage)

R =

Resistance (Ohms)

Ohm's law states that the electrical current (I) flowing in an circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). Therefore, if the voltage is increased, the current will increase provided the resistance of the circuit does not change. Similarly, increasing the resistance of the circuit will lower the current flow if the voltage is not changed. The formula can be reorganized so that the relationship can easily be seen for all of the three variables.

The Java applet below allows the user to vary each of these three parameters in Ohm's Law and see the effect on the other two parameters. Values may be input into the dialog boxes, or the resistance and voltage may also be varied by moving the arrows in the applet. Current and voltage are shown as they would be displayed on an oscilloscope with the X-axis being time and the Y-axis being the amplitude of the current or voltage. Ohm's Law is valid for both direct current (DC) and alternating current (AC). Note that in AC circuits consisting of purely resistive elements, the current and voltage are always in phase with each other.

Exercise: Use the interactive applet below to investigate the relationship of the variables in Ohm's law. Vary the voltage in the circuit by clicking and dragging the head of the arrow, which is marked with the V. The resistance in the circuit can be increased by dragging the arrow head under the variable resister, which is marked R. Please note that the vertical scale of the oscilloscope screen automatically adjusts to reflect the value of the current.

See what happens to the voltage and current as the resistance in the circuit is increased. What happens if there is not enough resistance in a circuit? If the resistance is increased, what must happen in order to maintain the same level of current flow?Explanation:

7 0
3 years ago
Read 2 more answers
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