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inna [77]
3 years ago
9

Jo wants to find out about floating and sinking. She puts a rubber duck and a bar of soap in a

Physics
1 answer:
maks197457 [2]3 years ago
7 0

Answer:

the soap sinks because it is more dense than the duck.

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nert xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH o f values for xenon difluorid
loris [4]

Answer:

For Xenon fluoride, the average bond energy is 132kj/mol

For tetraflouride,the average bond energy is 150.5kj/mol.

For hexaflouride, the average bond energy is 146.5 kj/mol

Explanation:

For xenon fluoride

105/2 = 52.5

For F-F

159/2 = 79.5

Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole

For tetraflouride

284/4 = 71

For F-F

159/2 = 79.5

Average bond energy = 79.5 + 71 = 150.5kj/mol

For hexaflouride

402/6 = 67

F-F = 159/2 = 79.5

Average bond energy = 67 + 79.5 = 146.5kj/ mol

3 0
3 years ago
An object moves in a circle at a constant speed of 1.0 m/s. The radius of the circle is 1.0 m. If a force of 1.0 N acts toward t
Vlad1618 [11]

Answer:5

Explanation:

Given

speed of object v=1\ m/s

radius of circle r=1\ m

Force towards the center F=1\ N

Work done is given by the dot product of Force and displacement

and we know know displacement of the object is along the circle which is perpendicular to the force acting therefore Work done will be zero

W=F\cdot s\cos 90

W=0

4 0
3 years ago
The candle burning
vodka [1.7K]

Answer:

A

Explanation:

its oxygen I hope i am correct have a great day.

3 0
3 years ago
A machine accelerates a 5 kg missile from rest to a speed of 5 km/s. The net force accelerating the missile 500,000 N. How long
Gnoma [55]
Final velocity = 5km/sec = 5000 m/sec
Initial velocity = 0, mass = 5kg and force = 500,000 N
F = m(Vf-Vi)/time
Time = m(Vf-Vi)/force = 5*5000/500000 = 0.05 seconds
So, it takes 0.05 sec to arrive at the speed of 5km/s.
3 0
3 years ago
The 300 m diameter Arecibo radio telescope is observing the Andromeda galaxy at a wavelength of 29 cm. show answer No Attempt 50
jekas [21]

Answer:

The angle between two just-resolvable stars for the Arecibo telescope is 1.179x10^{-3}rad.

Explanation:

The resulting image in a telescope obtained from an object is a diffraction pattern.

That diffraction pattern is obtained because the light encounters different obstacles on its path inside the telescope (interact with the walls and edges of the instrument).

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.    

 

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction patterns maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in an analytical way by means of the Rayleigh criterion.          

\theta = 1.22\frac{\lambda}{D}   (1)

Where \lambda is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

\lambda = 29cm \cdot \frac{1m}{100cm} ⇒ 0.29m

Finally, equation 1 can be used.

\theta = 1.22(\frac{0.29m}{300m})

\theta = 1.179x10^{-3}rad              

Hence, the angle between two just-resolvable stars for the Arecibo telescope is 1.179x10^{-3}rad    

3 0
3 years ago
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