Step-by-step explanation:
∫₀³⁰ (r/V C₀ e^(-rt/V)) dt
If u = -rt/V, then du = -r/V dt.
∫ -C₀ e^u du
-C₀ ∫ e^u du
-C₀ e^u + C
-C₀ e^(-rt/V) + C
Evaluate between t=0 and t=30.
-C₀ e^(-30r/V) − -C₀ e^(-0r/V)
-C₀ e^(-30r/V) + C₀
C₀ (-e^(-30r/V) + 1)
I got the same answer. Try changing the lowercase v to an uppercase V.
Answer:
<h2><em><u>2</u></em></h2>
Step-by-step explanation:
![= \sqrt[5]{32}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B5%5D%7B32%7D%20)
![= \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B5%5D%7B2%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202%7D%20)
= <em><u>2</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Answer:24, it depend upon the picture
Step-by-step explanation:
if the ac and bc are diagonals the area of rhombus equal to 24.because area of the rhombuss = pq/2where p and q are the diagonals
The coreect point is (4,7)
Area of base = 9pi
curve surface area = 3*pi*15=45pi
total area 54pi
i guess the n here represents pi the answer would just be a since its the most relevant
