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marta [7]
3 years ago
13

A block of mass 2kg is acted upon by two forces: 3N (directed to the left) and 4N (directed to the right). What can you say abou

t the block's motion?
Physics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:

The block will be move in to right side.

Explanation:

Given that,

Mass of block = 2 kg

First force = 3 N

Second force = 4 N

We need to calculate the acceleration

For first force,

Using newton's second law

F= ma

a = \dfrac{F}{m}

Put the value into the formula

a=\dfrac{3}{2}

a=1.5\ m/s^2

We need to calculate the acceleration

For second force,

a=\dfrac{4}{2}

a=2\ m/s^2

So, we can say that the block will be move to right side because the acceleration is maximum in to right side.

Hence, The block will be move in to right side.

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A noninverting op-amp circuit with a gain of 96 V/V is found to have a 3-dB frequency of 8 kHz. For a particular system applicat
umka21 [38]

Answer:

Av_2 =24\ V/V

Explanation:

given,

op-amp circuit with a gain of = (Av₁) = 96 V/V

Band width  = (Bw₁) = 8 kHz

Required bandwidth(Bw₂) = 32 kHz

Highest gain available =(Av₂) = ?

For the given system Bandwidth product is constant

                           Av₁ Bw₁ = Av₂ Bw₂

                           96 x 8 = Av₂ x 32

                           Av_2= \dfrac{96\times 8}{32}

                           Av_2 =24\ V/V

the highest gain available under these conditions Av_2 =24\ V/V

6 0
4 years ago
The train traveled 500 kilometers north to Odessa in 2 hours . What’s the train’s speed ? What is the velocity ?
ElenaW [278]

Explanation:

Speed is distance over time.

500 km / 2 hr = 250 km/hr

Velocity is speed and direction.

250 km/hr north

7 0
3 years ago
A projectile is launched at ground level with an initial speed of 54.5 m/s at an angle of 35.0° above the horizontal. It strikes
Alchen [17]
<h2>Answer: x=125m, y=48.308m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=54.5m/s is the projectile's initial speed

\theta=35\° is the angle

t=2.80s is the time since the projectile is launched until it strikes the target

x  is the final horizontal position of the projectile (the value we want to find)

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=0  is the initial height of the projectile (we are told it  was launched at ground level)

y  is the final height of the projectile (the value we want to find)

g=9.8m/s^{2}  is the acceleration due gravity

Having this clear, let's begin with x (1):

x=(54.5m/s)cos(35\°)(2.8s)   (3)

x=125m   (4)  This is the horizontal final position of the projectile

For y (2):

y=0+(54.5m/s)sin(35\°)(2.8s)-\frac{(9.8m/s^{2})(2.8s)^{2}}{2}   (5)

y=48.308m   (6)  This is the vertical final position of the projectile

4 0
3 years ago
Explain why steel is mor dense than water
natta225 [31]
Steel is more dense because it’s heavy while water is light
7 0
3 years ago
Read 2 more answers
What do it mean by the value of gravitational constant is 6.67×10^-11Nm^2/kg^2<br>​
luda_lava [24]

Answer:

gravitational constant value means it was never change in any particular area of the Earth

8 0
2 years ago
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