Help me figure this out

4 is the _____ of 4n

murzikaleks [220]

Answer:

4 is the coefficient of 4n

Step-by-step explanation:

8 0

2 years ago

Help please I realy nead help

Makovka662 [10]

Answer:

B) 77.5 square feet

Step-by-step explanation:

cut shape into rectangle and triangle

area of rectangle = x*y

area of rectangle = 5*13

area of rectangle = 65

area of triangle = (z-x)*(y-w)/2

area of triangle = 5*3/2

area of triangle = 7.5

Total area = 65 + 7.5

Total area = 77.5, B)

3 0

1 year ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =

Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

<u>Step-by-step explanation:</u>

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

3 years ago

All cars can be classified into one of four groups: the subcompact, the compact, the midsize, and the full-size. There are

Olegator [25]

Answer:

p value = 0.302

Step-by-step explanation:

Given that all cars can be classified into one of four groups: the subcompact, the compact, the midsize, and the full-size. There are five cars in each group. Head injury data (in hic) for the dummies in the driver's seat are listed below.

H_0: All cars have same mean values

H_a: atleast two cars have different mean values

(Two tailed anova test)

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

Subcompact 5 3444 688.8 48502.7

compact 5 2879 575.8 4582.7

Midsize 5 2534 506.8 18720.2

Full size 5 2689 537.8 23905.2

ANOVA

Source of Variation SS df MS F P-value F crit

Between Groups 94825 3 31608.33 1.321 0.302 3.24

Within Groups 382843.2 16 23927.7

Total 477668.2 19

Since p value of 0.302 is greater than 0.05 significance level we accept null hypothesis.

p value = 0.302

6 0

2 years ago

You paid $44 to a loan company for the use of $1,153 for 119 days, what annual rate of interest did they charge? (Assume a 360-d

Zigmanuir [339]

Answer:

Ans. A) The annual rate that the company charged was 11.996%; B) if they charged you 11.186% annual rate, you would have to pay $41.14

Step-by-step explanation:

Hi, first we have to find out what is the effective 119 days rate and then turn it into an annual rate. This is as follows.

$r(Effective119Days)=\frac{44}{1,153} x100=0.038161$

So the charged rate was 3.816% effective, 119 days, now let´s make it an annual rate.

$r(annual)=(1+0.038161)^{\frac{360}{119} } -1=0.119965$

This means that the equivalent rate to 3.816% effective 119 days ys 11.996% effective annually (or just annual).

Now, if they were to charge you 11.186% annual, you would have to make this rate effective 119 days, and then, multiply it by the principal ($1,153). Let´s change the rate first.

$r(Effective119Days)=(1+0.11186)^{\frac{119}{360} -1}=0.03568$

And the money that you will have to pay in interest is $1,153*0.03568=$41.14

Best of luck

7 0

2 years ago