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The expression of integral as a limit of Riemann sums of given integral 
is 4 
∑
from i=1 to i=n.
Given an integral .
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=![[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}](https://tex.z-dn.net/?f=%5Bn%5E%7B2%7D%28n%2B4i%29%5D%2F2n%5E%7B3%7D%2B%28n%2B4i%29%5E%7B3%7D)
∑f(a+iΔx)Δx=
∑
=4∑
Hence the expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
Learn more about integral at brainly.com/question/27419605
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Answer:
I think it would be 2
Step-by-step explanation:
hope it help and was rigjt
Answer:
f(x) = x³ - 5x² - 9x + 45
Step-by-step explanation:
Given x = a, x = b are the zeros of a polynomial, then
(x - a), (x - b) are the factors and f(x) is the product of the factors.
Here the zeros are x = - 3, x = 3 and x = 5, thus
(x + 3), (x - 3) and (x - 5) are the factors and
f(x) = (x + 3)(x - 3)(x - 5) ← expand the first pair of factors using FOIL
= (x² - 9)(x - 5) ← distribute
= x³ - 5x² - 9x + 45
Answer:
B
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
Then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real irrational roots
• If b² - 4ac > 0 and a perfect square then 2 real rational roots
• If b² - 4ac = 0 then 1 real double root
• If b² - 4ac < 0 then 2 complex roots
Given
x² + 3x - 7 = 0 ← in standard form
with a = 1, b = 3, c = - 7 , then
b² - 4ac
= 3² - (4 × 1 × - 7) = 9 + 28 = 37
Since b² - 4ac > 0 then 2 real irrational roots
