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VladimirAG [237]
3 years ago
13

Help me figure this out

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer:

i think a

Step-by-step explanation:

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36 Divided by 6 :]]]]]]]]]]]]]]]]]]]]]]]]]]]]]]
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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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2 years ago
What is the value of x
oksian1 [2.3K]

Answer:

I think it would be 2

Step-by-step explanation:

hope it help and was rigjt

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Find a polynomial with a degree of 3 and zeros -3,3,5
Aliun [14]

Answer:

f(x) = x³ - 5x² - 9x + 45

Step-by-step explanation:

Given x = a, x = b are the zeros of a polynomial, then

(x - a), (x - b) are the factors and f(x) is the product of the factors.

Here the zeros are x = - 3, x = 3 and x = 5, thus

(x + 3), (x - 3) and (x - 5) are the factors and

f(x) = (x + 3)(x - 3)(x - 5) ← expand the first pair of factors using FOIL

     = (x² - 9)(x - 5) ← distribute

    = x³ - 5x² - 9x + 45

   

6 0
3 years ago
Question 7 of 10
Mama L [17]

Answer:

B

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

Then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real irrational roots

• If b² - 4ac > 0 and a perfect square then 2 real rational roots

• If b² - 4ac = 0 then 1 real double root

• If b² - 4ac < 0 then 2 complex roots

Given

x² + 3x - 7 = 0 ← in standard form

with a = 1, b = 3, c = - 7 , then

b² - 4ac

= 3² - (4 × 1 × - 7) = 9 + 28 = 37

Since b² - 4ac > 0 then 2 real irrational roots

8 0
3 years ago
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