The player took a total of 70 shots and missed about 28 shots.
<h3>
Percentage</h3>
Percentage is used in expressing a fraction number or decimal in fraction of 100. It is expressed using the '%' sign.
Given a total shot of 100, since the player took 70% of the shot, hence:
Total shot taken by the player = 70% of 100 = 0.7 * 100 = 70 shots.
Total shot shot missed = (100% - 60%) of 70 = 40% of 70 = 0.4 * 70 = 28 shots.
The player took a total of 70 shots and missed about 28 shots.
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Answer:
0.3075 = 30.75% probability that a person will wait for more than 7 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The standard deviation is the square root of the variance.
In this problem, we have that:

Find the probability that a person will wait for more than 7 minutes.
This is 1 subtracted by the pvalue of Z when X = 7. So



has a pvalue of 0.6915
1 - 0.6915 = 0.3075
0.3075 = 30.75% probability that a person will wait for more than 7 minutes.
Answer:
47 minutes
Step-by-step explanation:
3/4 of an hour is 45 minutes which makes 15 minutes remain and if it is 13 minutes left the 45 + 2 is 47
Answer:
Y=5
Step-by-step explanation:
x = -12( given)
-6 X( -12) -3y = 57
72-3y = 57
-3y=57-72
-3y= -15
Y=-15/-3
Y=5
Answer:

Step-by-step explanation:
Circumference has the formula:
C = 2πr,
Where
C is the circumference
and
r is the radius
Given Circle Y has Circumference of 6, we can find the radius:
C = 2πr
6 = 2πr
r = 6/2π
r = 3/π
So, the radius (r_y) of Circle Y is 3/π, the first choice is right.