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Umnica [9.8K]
3 years ago
8

Complete the reaction by writing the formulas of the products. CH 3 COOH + NH 3 − ⇀ ↽ − CH_{3}COONH_{4}^{+} CH 3 COONH + 4 The K

a of CH 3 COOH (acetic acid) is 1.8 × 10 − 5 . The K a of the conjugate acid formed in this reaction is 5.6 × 10 − 10 . Indicate whether the products or the reactants are favored.
Chemistry
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

Products are favored.

Explanation:

The acid-base reaction of CH₃COOH (acid) with NH₃ (base) produce:

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr = ?

It is possible to know Kr of the reaction by the sum of acidic dissociations of the half-reactions. That is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ Ka = 1.8x10⁻⁵

NH₃ + H⁺ ⇄ NH₄⁺ 1/Ka = 1/ 5.6x10⁻¹⁰ = 1.8x10⁹

___________________________________

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr =  1.8x10⁻⁵×1.8x10⁹ = <em>3.2x10⁴</em>

<em> </em>

As Kr is defined as:

Kr =  [CH₃COO⁻] [NH₄⁺] / [CH₃COOH] [NH₃]

And Kr is > 1  

[CH₃COO⁻] [NH₄⁺] > [CH₃COOH] [NH₃],

showing <em>products are favored</em>.

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