По сссстото пъпси и спп.<br> a. 120 mm =<br> What is 120 milliters to meters

Which is true about sugar dissolving in water?

<span>The correct answer is "Sugar is the solute and water is the solvent". Why? Sugar can be dissolved by water itself, especially in hot water, which is why water is considered to be a solvent, while sugar is considered to be a solute because it can be dissolved.</span>

6 0

3 years ago

Express the product of 9.0 x 10^-4m and 8.1 x 10^4m using the correct number of significant digits

Assoli18 [71]

Answer:

7.3 × 10¹ m²

Explanation:

The language "product" means that we must multiply the numbers given to get our answer.

9.0 × 10⁻⁴ m × 8.1 × 10⁴ m = 7.3 × 10¹ m²

The significant figures rule for multiplication is that we must us the amount of significant figures in the number with the least significant figures, in this question this is 2 significant digits from both 9.0 × 10⁻⁴ m and 8.1 × 10⁴ m.

7 0

4 years ago

If a solution containing 45.101 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of s

AnnyKZ [126]

Answer:

14.533 grams of solid precipitate of mercury(II) dichromate will form.

Explanation:

$Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)$

Moles of mercury(II) acetate = $\frac{45.101 g}{318.70 g/mol}=0.14152 mol$

Moles of sodium dichromate = $\frac{12.026 g}{261.97 g/mol}=0.045906 mol$

According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) acetate

This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.

According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) dichromate

Mass of 0.045906 moles of mercury(II) dichromate:

0.045906 mol × 316.59 g/mol = 14.533 g

14.533 grams of solid precipitate of mercury(II) dichromate will form.

3 0

4 years ago

The graph shows how milk production from a herd of cows has changed.

sammy [17]

Answer:

drink it

Explanation:

6 0

3 years ago

Which type of scientist would most likely investigate how to synthesis materials found in plants

denis23 [38]

Botanist is the type of scientist that studies materials found in plants

4 0

3 years ago

Read 2 more answers

По сссстото пъпси и спп. a. 120 mm = What is 120 milliters to meters