Answer:
Both b and d can be correct
Explanation:
Generally, diffusion does not require energy (<em>making option a wrong</em>) because it is the movement of particles from a region of high concentration to a region of low concentration hence diffusion moves particles in the direction of a concentration gradient. An example of this is the passive transport (for instance, uptake of glucose by a liver cell).
However, in some cases, when diffusion is against the concentration gradient (i.e when particles move from a region of low concentration to a region of high concentration), diffusion will require energy in a case like this (<em>making option c wrong</em>). An example of this is active transport (transport of protein called sodium-potassium pump which involves pumping of potassium into the cell and sodium out of the cell).
The explanation above shows that diffusion can require energy to move particles (in or out) of the cell through the cell membrane.
32 h this is because this problem
Answer:
See image attached and explanation
Explanation:
I have attached a detailed mechanism of the reaction to this answer. This reaction occurs by SN1 mechanism. It implies that the transition state involves a carbocation.
However, the initial carbocation formed is a primary carbacation. Remember that the order of stability of carbocations is methyl< primary < secondary< tertiary. This means that tertiary carbocations are the most stable carbocations. Tertiary carbocations are those in which the carbon atom bearing the carbon atom is attached to three other carbon atoms.
In the mechanism below, the substrate converts from a primary to a tertiary cabocation (most stable) by a 1,2-alkyl shift as shown giving the 3-ethoxy-3-methylpentane product.
Answer:
A molecule can be defined as the combinations of two or more atoms are held together by chemical bonds. A molecule is the smallest portion of a substance which showcases all the properties of the substance.
Explanation: