The sum of two numbers is 37 and the difference is 9. What are the numbers

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Answer:

23 and 14

Step-by-step explanation:

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Points (−3, 5) and (3, 5) on the coordinate grid below show the positions of two players on a tennis court:

Anna35 [415]

Answer:

4. Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

Step-by-step explanation:

Player 1's position is (-3, 5).

It means that it is 3 units left from the origin and 5 units above the origin.

Player 2's position is (3, 5).

It means that it is 3 units right from the origin and 5 units above the origin.

Hence, the two points are on the same horizontal line bisected by the y-axis.

So, Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

3 0

3 years ago

HELP I HAVE 5 MIN TO TURN THIS IN

tekilochka [14]

Is there supposed to be a photo?

4 0

3 years ago

Read 2 more answers

M∠IJK=155° and m∠ZJK=35°. Find m/∠IJZ

PtichkaEL [24]

120° because 155-35=120 since IJZ is inside the IJK so you would have to subtract the ZJK from the IJZ.

8 0

2 years ago

In the interval 0 x 360 find the values of x for which cos x =0.7252

Sergeeva-Olga [200]

Answer:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

Step-by-step explanation:

We have a positive value for the cosine of x, so we know that the value of x should be in the first quadrant (0 ≤ x ≤ 90) or in the fourth quadrant (270 ≤ x ≤ 360).

Now, let's find the value of x that gives cos(x) = 0.7252 using the inverse function of the cosine, that is, the arc cosine function.

The value of x can be calculated using:

$x = arccos(0.7252)$

Using this function in a calculator (you may find it as: $cos^{-1}(x)$ ), we have that:

$x_1 = 43.5145\°$

So this is the value of x in the first quadrant. To find the other value of x, in the fourth quadrant, that gives the same result, we just need to calculate 360° minus the value we found:

$x_2 = 360\° - 43.5145\° = 316.4855\°$