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3 years ago

If the electronegativity difference between the elements in the ionic compound nax has the ratio of 2 to 1 what element is x

Chemistry

1 answer:

S_A_V [24]3 years ago

4 0

X is any anion or molecule that has a negative charge of 2

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14. Would you expect each of the following atoms to gain or lose electrons when forming ions ? what ion is the most likely in ea

yanalaym [24]

Answer:

The answer to your question is below

Explanation:

Metals lose electrons and Nonmetals gain them.

a. Ra is in group IIA it will lose electrons, the ion will be Ra⁺²

b. Br is in group VIIA it will gain electrons, the ion will be Br⁻¹

c. In is in group IIIA it will lose electrons, the ion will be In⁺³

d. Te is in group VIA it will gain electrons, the ion will be Te⁻²

e. Ca is in group IIA it will lose electrons, the ion will be Ca⁺²

f. As is in group VA it will gain electrons, the ion will be As⁻³

g. Al is in group IIlA it will lose electrons, the ion will be Al⁺³

h. Rb is in group IA it will lose electrons, the ion will be Rb⁺¹

7 0

2 years ago

Assume that a daily diet of 2000 calories (i.e. 8.37 x 106 J) is converted completely to body heat.

slava [35]

Answer:

(a) the mass of the water is 3704 g

(b) the mass of the water is 199, 285.7 g

Explanation:

Given;

Quantity of heat, H= 8.37 x 10⁶ J

Part (a) mass of water (as sweat) need to evaporate to cool that person off

Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg

H = m x Lvap.

$m = \frac{H}{L._{vap}} =\frac{8.37 * 10^6.J}{2.26*10^6\ \frac{J}{kg}} = 3.704 \ kg$

mass in gram ⇒ 3.704 kg x 1000g = 3704 g

Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J

specific heat capacity of water, C, 4200 J/kg.°C

H = mcΔθ

where;

Δθ is the change in temperature = 35 - 25 = 10°C

$m =\frac{H}{c* \delta \theta} = \frac{8.37 *10^6}{4200*10} = 199.2857 kg$

mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g

5 0

3 years ago

What is the simplest aromatic compound?<br> toluene<br> benzene<br> cyclohexane<br> cyclopropane

pav-90 [236]

It’s Benzene, I do believe :) hope this helped, good luck!

3 0

3 years ago

What is the oh- in a solution with a poh of 5.71

Rudik [331]

Answer:- The hydroxide ion concentration of the solution is $1.95*10^-^6$ .

Solution:- The formula used to calculate pOH from hydroxide ion is:

$pOH=-log[OH^-]$

When pOH is given and we are asked to calculate hydroxide ion concentration then we multiply both sides by negative sign and take antilog and what we get on doing this is:

$[OH^-]=10^-^p^O^H$

pOH is given as 5.71 and we are asked to calculate hydrogen ion concentration. Let's plug in the given value in the formula:

$[OH^-]=10^-^5^.^7^1$

$[OH^-]$ = 0.00000195 or $1.95*10^-^6$

So, the hydroxide ion concentration of the solution is $1.95*10^-^6$ .

3 0

3 years ago

Assuming equal concentrations, rank these solutions by ph.? assuming equal concentrations, rank these solutions by ph. koh (aq h

polet [3.4K]

I remember coming across this question and the options were:
KOH, HCN, NH₃, HI, Sr(OH)₂

Now, a substance with a low pH is one that dissociates completely in water to release hydrogen ions, while basic substances dissociate completely to release hydroxide ions. Therefore, in the order of increasing pH:
HI, HCN, NH₃, Sr(OH)₂, KOH

7 0

2 years ago