Please help with this math question!

Mathematics

1 answer:

alisha [4.7K]3 years ago

5 0

$Use\ a^\frac{n}{m}=\sqrt[m]{a^n}.\\\\4^\frac{3}{5}=\boxed{\sqrt[5]{4^3}}=\boxed{\sqrt[5]{64}}$

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Sum of money is placed at simple interest for 3 years at 10% per annum and then the amount is invested for 2 years at the same r

JulsSmile [24]

Answer:

sum was 300000

Step-by-step explanation:

let sum of money is placed is x rs

Term T = 3 years, rate R = 10%

Then simple interest for for 3 years is

$SI= \frac{PTR}{100}\\ SI=\frac{x\times 3\times 10}{100} \\SI = 0.3x$

Sum of x will become x+0.3x = 1.3x after 3 years. now this 1.3x is kept for compound interest for two years. ie

$A =P[1+R]^t\\471900=1.3x[1+\frac{10}{100} ]^2\\x=\frac{471900}{1.573} \\x=300000$

Sum was 300000

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4 years ago

Craig Deloy deposited $800 in a new savings account. The bank pays 4.5% simple interest computed on a daily basis. He made no ot

Aleks [24]

keeping in mind that 250 days is not even a year, since there are 365 days in a year, assuming so, then 250 days is really 250/365 years.

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$800\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\to \frac{250}{365}\dotfill &\frac{50}{73} \end{cases} \\\\\\ I=(800)(0.045)\left( \frac{50}{73}\right)\implies I\approx 24.658$

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kipiarov [429]

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denis23 [38]

Answer:

boom I hope this was the right thing

Step-by-step explanation:

i went on your profile thing yep

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3 years ago

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