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goblinko [34]
3 years ago
7

What is a GCF of 10 and 20

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0

Answer:

10

Step-by-step explanation:

We found the factors and prime factorization of 10 and 20. The biggest common factor number is the GCF number. So the greatest common factor 10 and 20 is 10.

USPshnik [31]3 years ago
4 0

The greatest common factor of 10 and 20 is 10.

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5 0
3 years ago
Nathan opens a new savings account and makes an initial deposit of $400.
AfilCa [17]

Answer:

The answer to the first one is 6

Step-by-step explanation:

If the time frame given is 9 months, then we can find that 9 months is 3/4 of a year. 3/4 x 2% = 0.015.     0.015 x 400 = 6. He would have made 6 dollars in 9 months.

Answer the the second one:

4.5% x 5 (years) = 0.225.     0.225 x 10,000 = 2,250. Since this is a car loan and not a bank interest for example, we add it to the total cost. I'm pretty sure its the third one.

6 0
3 years ago
P+12=17 what does p equal in this situation ​
victus00 [196]

Answer:

5

Step-by-step explanation:

5+12= 17

8 0
2 years ago
Read 2 more answers
Pls ans both the questions im very confused
lions [1.4K]

Answer:

Step-by-step explanation:

In Δ PQS and ΔPQT

∠QPS = ∠RPT       {Common angle}

∠PSQ = ∠PTR = 90°         {QS & RT are altitude}

QS = RT                            {given}

ΔPQS ≅ ΔPRT               {A A S congruent}

PQ = PS                         {CPCT}

So, PQR is an isosceles triangle.

9)

a) Flas card (I) and (iii) are congruent.

b)  A S A congruent

c) BC ≅ RP

5 0
2 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
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