Answer: The point slope form of the equation of graphed line is
and the slope-intercept form is 
Step-by-step explanation: We are given to find the point-slope form and slope-intercept form of the equation of the graphed line.
We know that
the slope of a line passing through the points (a, b) and (c, d) is given by
From the graph, we note that the line passes through the points (3, 0) and (-2, 3).
So, the slope of the line is

Sine the line passes through the points (3, 0), so its equation point-slope form is given by

And, the slope-intercept form is

Thus, the point slope form of the equation of graphed line is
and the slope-intercept form is 