A teaspoon of caffeine is <em>NOT</em> deadly as teaspoon of ricin
<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories
<u>Explanation:</u>
To calculate the amount of heat absorbed at normal boiling point, we use the equation:
![q=m\times L_{vap}](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20L_%7Bvap%7D)
where,
q = amount of heat absorbed = ?
m = mass of water = 10 grams
= latent heat of vaporization = 539 Cal/g
Putting values in above equation, we get:
![q=10g\times 539Cal/g=5390Cal](https://tex.z-dn.net/?f=q%3D10g%5Ctimes%20539Cal%2Fg%3D5390Cal)
Hence, the amount of energy absorbed by water is 5390 Calories
1. I think it is true?
2. Low melting points
3. True
4. Atomic number, I think it’s periods?
5. Groups?
Sorry, I might not get all of them right :(
Hope this helps you in any way!!