Question

Find the a15 of the sequence 7/8, 1 / 2, 1 / 8, -1 / 4​

Answer 1

Answer:

The term a15 of the sequence is $a_{15}=-\frac{35}{8}$.

Step-by-step explanation:

The given sequence is

$\frac{7}{8},\frac{1}{2},\frac{1}{8},\frac{-1}{4}$

It it an arithmetic sequence because the difference between two consecutive terms are same.

The first term of the given AP is

$a=\frac{7}{8}$

The common difference is

$d=\frac{1}{2}-\frac{7}{8}=-\frac{3}{8}$

The nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$a_{15}=\frac{7}{8}+(15-1)(-\frac{3}{8})$

$a_{15}=\frac{7}{8}-(14)(\frac{3}{8})$

$a_{15}=\frac{7}{8}-\frac{21}{4}$

$a_{15}=-\frac{35}{8}$

Therefore the term a15 of the sequence is $a_{15}=-\frac{35}{8}$.

Answer 2

Answer:

=-485/1944( Decimal: 0.249486)

Step-by-step explanation:

7/81/21/8-1/4