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Rasek [7]
4 years ago
12

what is the maximum force a hammer can apply to a steel nail 2.5 mm in diameter of the nails elastic limit is not to be exceeded

Physics
1 answer:
natita [175]4 years ago
7 0

Yield strength of mild steel is given as

Y = 250 MPa

here we know that

Y = \frac{F}{A}

250 * 10^6 = \frac{F}{\pi r^2}

now we can rearrange it as

F = \pi r^2 * 250* 10^6

here we know that

r = 1.25 mm = 1.25 * 10^{-3} m

F = \pi*(1.25*10^{-3})^2* 250* 10^6

F = 1.23 * 10^3 N

so maximum applied force will be F = 1.23 * 10^3 N

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Modifiable strength improvement factors include all of the following except...??
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Who was the first person to discover wormholes?
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myrzilka [38]

Answer:

(a) 0

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(c) 10ML(1 - cos(\theta))

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Explanation:

(a) When hanging straight down. The child is at the lowest position. His potential energy with respect to this point would also be 0.

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E_{\theta} = mgh = 10M(L - Lcos(\theta)) = 10ML(1 - cos(\theta))

(d) at angle \phi from the horizontal. Suppose he is higher than the horizontal line. This would mean he's at a vertical distance of Lsin(\phi) from the swinging point and higher than it. Therefore his vertical distance to the lowest point is L + Lsin(\phi) = L(1 + sin(\phi))

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