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Dennis_Churaev [7]
4 years ago
8

Hi.

Physics
2 answers:
Pani-rosa [81]4 years ago
6 0
<h2>Answer:</h2>

Options a and e are units which are C and T.

While options b, c ,d and f are variables or quantities.

<h3>Explanation:</h3>

The units are the signs or representation of a standard amount of an physical quantity like meter for length.

Here C and T are units because they are not in cursive form.

C is unit of charge Coulomb while T is Tesla the unit of magnetic field strength.

Variables are written in italics or cursive form. As:

  • <em>c = </em>any constant.
  • <em>C = c</em>urie constant.
  • <em>T=  </em>Temperature.
  • <em>t = </em>Time.
zhenek [66]4 years ago
4 0

Answer: Units: C, T and Variables: <em>c, C, t, T</em>

(a) C is the unit of charge Coulomb, (e) T is the unit of magnetic field strength Tesla.

In physics, units are written straight and variables are written in italics. Various italic symbols are used for various quantities like <em>t </em>for time, <em>T</em> for temperature, <em>c</em> for any constant and <em>C</em> for curie constant.

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They form an ionic bond by exchanging two electrons.

Explanation:

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All visible light (light that our eyes can detect) has a wavelength between 400-700 nanometers.  Wavelengths just smaller than 4
den301095 [7]

The Balmer light series comes under the visible light.

<u>Explanation:</u>

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Mostly, these lines has the wavelength of more than 400 nm but lesser than 700 nm. Generally of the four categories namely, 410, 434, 486, 656 nm which comes under the type of visible light. So, it can be concluded that the Balmer series light falls under visible light.

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4 0
3 years ago
What characteristics are shared by both heating and cooling curves? choose 4
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The characteristics shared by both heating and cooling curves is that phases changes when the temperature stays the same.

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6 0
2 years ago
IP Standing side by side, you and a friend step off a bridge at different times and fall for 1.6 s to the water below. Your frie
ratelena [41]

The distance to the water is the same for both ... call it s meters


They both take 1.6 s to reach the water ... so t = 1.6 seconds


They both step off the bridge ... so both have an initial vertical velocity is 0 m/s


Just consider the vertical motion and take DOWN as the positive direction


a = 9.8 m/s²


s = v(i)t + (1/2)at²


s = 0 + (1/2) * 9.8 * 1.6²


s = 12.5 m ←←← Edit: Forgot to say ... that's how high the bridge is above the water




Now get the time it takes the first jumper to reach 1.8 m:


s = v(i)t + (1/2)at²


1.8 = 0 + 4.9t²


t = 0.61 s


so when the 2nd person jumps it takes the first person another 1.6 - 0.61 = 0.99 s to reach the water




Now find how far the 2nd jumper falls in 0.99 s:


s = 0 + 4.9 * 0.99²


s = 4.8 m


so the separation distance between the two jumpers when the 1st jumper hits the water is 12.5 - 4.8 = 7.7 m


6 0
3 years ago
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