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3 years ago

What is the sum of all the positive two-digit integers divisible by both the sum and product of their digits?

Mathematics

1 answer:

Makovka662 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

Exhaustive search shows the numbers to be 12, 24, 36. The sum of these three numbers is 72.

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Answer this too, the BRAINIEST!

-Dominant- [34]

Check out the attached image below for the steps on how to do this derivation.

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Some notes:

For line 2, I used the identity $\sec^2\theta = \tan^2\theta+1$
For line 7, I applied the reciprocal to both sides.
For line 8, I used the identity $\cot\theta = \frac{1}{\tan\theta}$
For line 9, I used the identty $\cot^2\theta = \csc^2\theta - 1$ which is a rearrangement of $\cot^2\theta + 1 = \csc^2\theta$
For lines 1 through 6, I'm isolating tan^2, so that I can later transform that into cot^2, which leads to csc^2. All of this is done through the identities mentioned above.

8 0

3 years ago

A sporting goods store is selling all their exercise equipment for 30% off.

ra1l [238]

Answer:

weird

Step-by-step explanation:

4 0

3 years ago

Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick

erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

Solution:

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

$4 \times a + 4 \times b = 68$

4a + 4b = 68 ---------- eqn 1

The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets

Similarly, we frame a equation as:

$12 \times a + 5 \times b = 120$

12a + 5b = 120 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

12a + 12b = 204 -------- eqn 3

Subtract eqn 2 from eqn 3

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

Substitute b = 12 in eqn 1

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0

3 years ago

A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec

Bas_tet [7]

Speed of the ship in the second hour = (62.5 * x ) / 100 kph.

In third hour it is [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again so we can now form the equation

62.5x x x
------- * ---- * ---- = 32
100 100 100

62,5 x^3 = 32,000,000
x^3 = 512,000
x = 80 <----- Answer to (a)

(b) Ship travels 62.5 in first hour then this falls by a common ratio of 0.8 each hour so we have a geometric sequence

Dist travelled in 6 hours = a1 1 - r^n
-------- = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56

1 - r

Answer is 230.56 km

5 0

3 years ago

How did you get 0.36 from 7/20

Tema [17]

I'm confused when I did it I got .35 and you divide
hope it helped

7 0

3 years ago