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wel
4 years ago
14

The average distance an electron travels between collisions is 2.0 μm . What acceleration must an electron have to gain 2.0×10−1

8 J of kinetic energy in this distance? Express your answer to two significant figures and include the appropriate units. a = nothing nothing
Physics
1 answer:
LuckyWell [14K]4 years ago
3 0

Answer:

1.1\times 10^{18} m/s^{2}

Explanation:

Work=Kinetic energy

Fd=KE but we know that F=ma hence

ma d= KE

a=\frac {KE}{md}

Here a is acceleration, d is distance, KE is kinetic energy, m is mass

Taking m as 9.11\times 10^{-31} Kg, KE as 2\times 10^{-18} then d as 2\times 10^{-6} then

a=\frac {2\times 10^{-18}}{ 9.11\times 10^{-31}\times 2\times 10^{-6}}=1.1\times 10^{18} m/s^{2}

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