F=W=mg
12N(given)= m*9.8
m= 1.22 kg
Solution:
Let the slope of the best fit line be represented by '
'
and the slope of the worst fit line be represented by '
'
Given that:
= 1.35 m/s
= 1.29 m/s
Then the uncertainity in the slope of the line is given by the formula:
(1)
Substituting values in eqn (1), we get
= 0.03 m/s
Answer:
Explanation:
E₀ = 229.1 V/m
E = E₀ / √2 = 229.1 / 1.414 = 162 V/m
B = E / c ( c is velocity of em waves )
= 162 / (3 x 10⁸) = 54 x 10⁻⁸ T
rate of energy flow = ( E x B ) / μ₀
= 162 x 54 x 10⁻⁸ / 4π x 10⁻⁷
= 69.65 W per m².
<span>Assuming continuous operation (24/7), we can say that
Energy produced : Energy per hour * 24 (number of hours in a day) - 365 (number of days in a year.
Energy per hour: 2050 * 1.055 = 2162.75 kg.
So, we proceed to calculate the results
E: 2162.75 * 24 * 365 = 18,945,690 kj per year.
Now, we transform kj to megajoule, remembering that kilo is 10*3 and mega is 1'*6, so we divide the result by 1,000 in order to get the results in megajoules, and the answer would be:
18,945.69 megajoules can be produced per year.</span>
